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trasher [3.6K]
2 years ago
7

An unfair coin with .4 probability of tails is flipped 7 times what is the probability of obtaining exactly 5 heads

Mathematics
1 answer:
steposvetlana [31]2 years ago
5 0
P(heads) = 1 - 0.4 = 0.6P(5\ heads)=7C5\times0.6^{5}\times0.4^{2}=0.2613
The answer is 0.26 to 2 d.p.
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<span>For the plane, we have z = 5x + 9y

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\int\limits^1_0 { \int\limits_{x^4}^x {(5x+9y)} \, dy } \, dx = \int\limits^1_0 {\left[5xy+ \frac{9}{2} y^2\right]_{x^4}^{x}} \, dx  \\  \\ =\int\limits^1_0 {\left[\left(5x(x)+ \frac{9}{2} (x)^2\right)-\left(5x(x^4)+ \frac{9}{2} (x^4)^2\right)\right]} \, dx  \\  \\ =\int\limits^1_0 {\left(5x^2+ \frac{9}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx =\int\limits^1_0 {\left( \frac{19}{2} x^2-5x^5- \frac{9}{2} x^8\right)} \, dx \\  \\ =\left[ \frac{19}{6} x^3- \frac{5}{6} x^6- \frac{1}{2} x^9\right]^1_0

=\frac{19}{6} - \frac{5}{6} - \frac{1}{2} =\bold{ \frac{11}{6} \ cubic \ units}</span>
8 0
3 years ago
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