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inessss [21]
3 years ago
14

A triangular prism is 32 inches long and has a triangular face with a base of 18 inches and a

Mathematics
2 answers:
s344n2d4d5 [400]3 years ago
7 0
Its 1752 i just use scan lol
worty [1.4K]3 years ago
3 0

Answer:

1752

Step-by-step explanation:

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5h+4+52+64=180 what does that equal to
Softa [21]

Answer:

x=12

Step-by-step explanation:

5x+4+64+52=180

We move all terms to the left:

5x+4+64+52-(180)=0

We add all the numbers together, and all the variables

5x-60=0

We move all terms containing x to the left, all other terms to the right

5x=60

x=60/5

x=12

8 0
4 years ago
Mathematics (Reasked) Thank you for any answers, please be sure of it before you respond.
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4 0
3 years ago
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Schach [20]
The answer is 6 days
5 0
3 years ago
Read 2 more answers
For the class of 2013's prom Norman's dress shop sold cheaper dresses for $90 each and more expensive dresses for $140 each. The
Tema [17]

Answer:

Number of cheaper dresses sold  is 35

Number of expensive  dresses sold  is 15

Step-by-step explanation:

Given:

Cost of cheaper dresses = $90

Cost of  expensive dresses = $140

Total cost of  the dresses = $5250

To Find:

Number of cheaper dress = ?

Number of expensive  dress = ?

Solution:

Let

The number of  cheaper dresses be x

The number of  expensive dresses be y

(Number of cheaper dresses X cost of cheap dress) +  (Number of Expensive dresses X cost of  expensive dress)  =  $5250

x \times90 +y \times 140 = 5250=  $5250

It is given that the 20 more of the cheaper dresses than the expensive dresses is sold

So,

number of cheaper dress  =  20  +  number of expensive dress

x = 20 + y---------------------------------------(1)

(20+y) \times90 +y \times 140 = 5250 = 5250

(20 \times 90 +y\times 90) +y \times 140= 5250

1800 + 90y+ 140y = 5250

1800 + 230y = 5250

230y =5250 -1800

230y = 3450

y = \frac{3450}{230}

y = 15

Substituting y in (1)

x = 20 +15

x= 35

5 0
4 years ago
Find the missing length ‘x’
givi [52]

Answer:

x = 13

Step-by-step explanation:

The area (A) of a trapezium is calculated as

A = \frac{1}{2} h (b₁ + b₂ )

where h is the perpendicular height and b₁, b₂ the parallel bases

Here A = 55, h = 5. b₁ = x, b₂ = 9, then

\frac{1}{2} × 5 × (x + 9) = 55

2.5(x + 9) = 55 ( divide both sides by 2.5 )

x + 9 = 22 ( subtract 9 from both sides )

x = 13

7 0
3 years ago
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