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Oliga [24]
3 years ago
11

Write an equation in slope-intercept form that includes the points (-1,4) and (2, −2).

Mathematics
1 answer:
suter [353]3 years ago
4 0
The two formulas i used should be in your book

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Given: ⅓ (18x + 27) = 81 Prove: x = 12
sasho [114]

Answer:

Firstly, rewrite the equation:

⅓ (18 + 27) = 81

Substitute x for the given number of it's supposed equivalent.

In this case x = 12.

⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

(18 x 12) + 27 = 243

Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .

⅓ (243) = 81

When you multiple these number they are equivalent to 81.

81 = 81

Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.

4 0
3 years ago
Help plzzzzzzzzzzzzzz ​
Lana71 [14]

i think

SAS

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6 0
2 years ago
Consider the polynomial below.
kotykmax [81]

Answer:

(-4x - 2)(-5x) + (-4x - 2)(3)  

Step-by-step explanation:

Your polynomial is

(-4x - 2)(-5x + 3)

The distributive property states that

a(b + c) = ab + ac

Let a = -4x - 2.  Then

(-4x - 2)(-5x + 3) = a(5x + 3) = a(-5x) + a(3)

Substitute the value of a.

a(-5x) + a(3) = (-4x - 2)(-5x) + (-4x - 2)(3)

You have just distributed the first binomial (-4x - 2) among the terms of the second binomial.

3 0
3 years ago
I am not getting this math?<br>​
gladu [14]

Answer:

100

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
F(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, ∞) and g(x) = 2x2 + 8x + 6,
svetlana [45]

Answer:

B) Both functions have the same domain.

C) Both functions have the same x-intercepts.

D) Both functions are decreasing on the interval (−∞, −2).

Step-by-step explanation:

step 1

Find the vertex of f(x)

we know that

The x-coordinate of the vertex is the midpoint of the roots

we have

x=-1 and x=-3

so

the midpoint is

(-1-3)/2=-2

The y-coordinate of the vertex is -4 (because the range is [−4, ∞))

therefore

The vertex of f(x) is the point (-2,-4)

Is a vertical parabola open upward

The vertex is a minimum

The domain is all real numbers

step 2

we have

g(x)=2x^2+8x+6

Find the vertex

Factor the leading coefficient

g(x)=2(x^2+4x)+6

Complete the square

g(x)=2(x^2+4x+4)+6-8

g(x)=2(x^2+4x+4)-2

Rewrite as perfect squares

g(x)=2(x+2)^2-2

Is a vertical parabola open upward

The vertex is the point (-2,-2)

The domain is all real numbers

The range is the interval [−2, ∞)

Find the x-intercepts

For g(x)=0

0=2(x+2)^2-2

2(x+2)^2=2

(x+2)^2=1\\x+2=\pm1\\x=-2\pm1

so

The roots or x-intercepts are

x=-1 and x=-3

<u><em>Verify each statement</em></u>

A) Both functions have the same vertex

The statement is false

The vertex of f(x) is (-2,-4) and the vertex of g(x) is (-2,-2)

B) Both functions have the same domain.

The statement is true

The domain is all real numbers

C) Both functions have the same x-intercepts

The statement is true  (see the explanation)

D) Both functions are decreasing on the interval (−∞, −2)

The statement is true

Because the x-coordinate of the vertex is the same in both functions, and both functions open upward

7 0
3 years ago
Read 2 more answers
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