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Feliz [49]
3 years ago
11

Graph this line using the slope and y-intercept: y = 1/9x + 4​

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0
If you don’t know how to graph slope intercept equations here’s a simple step by step way.

Tiny explanation for step 1:

In y= 1/9x + 4 (y= mx+b) the 4 (b) is the y-intercept. In y= 1/9x + 4 (y= mx+b) the 1/9 (m) is the slope.

1. So go to (0,0) and go 4 units up and circle the point (0,4) which is going to be your lines y-intercept. (the vertical line in a graph is the y-axis, all y-intercepts are on this axis.)

Quick explanation for step 2: Once you have this point (0,4) your going to now use the slope of the equation (which is 1/9). Slopes are in rise over run formate or in more simplistic terms the top number (this only works with fractions) is how many spaces you go up and the bottom is how many spaces you go to the right (this is a positive slope so I won’t explain for negatives).

2. At point (0,4) your y-intercept go 1 unit up and 9 units to the right. Continue this with the new point u made if room (draw an arrow at the end). Then go back to (0,4) and do the other side of the line. This time go down 1 unit and left 9 units from (0,4) your y-intercept.

Hope this was at least somewhat helpful and not completely confusing!
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When John mom went grocery shopping she bought 5 cans of corn for $1.00 each she bought 4 cases of water for $4.00 she also boug
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Answer:

$1

Step-by-step explanation:

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4 cases of water  --  4 * $4 = $16

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What is the circumference<br> of the circle? Use 3.14<br> for pi<br> 4 in. Diameter
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3 years ago
Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s
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Given that the vertex of the parabola is (4,-3)

The parabola passes through the point (2,-1)

We need to determine the standard form of the equation of the parabola.

<u>Standard form of the equation of the parabola:</u>

The standard form of the equation is y=a(x-h)^2+k where the vertex is (h,k) and a is the constant.

Substituting the vertex (4,-3) in the above equation, we get;

y=a(x-4)^2-3  ---------------(1)

Substituting the point (2,-1) in the above equation, we have;

-1=a(2-4)^2-3

-1=a(-2)^2-3

-1=4a-3

  2=4a

  \frac{1}{2}=a

Thus, the value of a is \frac{1}{2}

Substituting the value of a in the equation (1), we get;

y=\frac{1}{2}(x-4)^2-3

Thus, the standard form of the equation of the parabola is y=\frac{1}{2}(x-4)^2-3

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