Graph this line using the slope and y-intercept: y = 1/9x + 4

1 answer:

8 0

If you don’t know how to graph slope intercept equations here’s a simple step by step way.

Tiny explanation for step 1:

In y= 1/9x + 4 (y= mx+b) the 4 (b) is the y-intercept. In y= 1/9x + 4 (y= mx+b) the 1/9 (m) is the slope.

1. So go to (0,0) and go 4 units up and circle the point (0,4) which is going to be your lines y-intercept. (the vertical line in a graph is the y-axis, all y-intercepts are on this axis.)

Quick explanation for step 2: Once you have this point (0,4) your going to now use the slope of the equation (which is 1/9). Slopes are in rise over run formate or in more simplistic terms the top number (this only works with fractions) is how many spaces you go up and the bottom is how many spaces you go to the right (this is a positive slope so I won’t explain for negatives).

2. At point (0,4) your y-intercept go 1 unit up and 9 units to the right. Continue this with the new point u made if room (draw an arrow at the end). Then go back to (0,4) and do the other side of the line. This time go down 1 unit and left 9 units from (0,4) your y-intercept.

Hope this was at least somewhat helpful and not completely confusing!

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Answer: c)[50,60]

Step-by-step explanation:

The Empirical rule says that , About 68% of the population lies with the one standard deviation from the mean (For normally distribution).

We are given that , The heights of students in a class are normally distributed with mean 55 inches and standard deviation 5 inches.

Then by Empirical rule, about 68% of the heights of students lies between one standard deviation from mean.

i.e. about 68% of the heights of students lies between $\text{Mean}\pm\text{Standard deviation}$

i.e. about 68% of the heights of students lies between $55\pm5$

Here, $55\pm5=(55-5, 55+5)=(50,60)$

i.e. The required interval that contains the middle 68% of the heights. = [50,60]

Hence, the correct answer is c) (50,60)

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Alternate means they are on opposite sides of the transversal...
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So answer C would be correct

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