This revolves around exact trig values - no easy way to say this, you just need to memorise them. They are there for sin cos and tan, but I will give you the main tan ones below - note this is RADIANS (always work in them when you can, everything is better):
tan0: 0
tanpi/6: 1/sqrt(3)
tanpi/4: 1
tanpi/3: sqrt(3)
tanpi/2: undefined
Now we just need to equate -2pi/3 to something we understand. 2pi/3 is 1/3 of the way round a circle, so -2pi/3 is 1/3 of the way round the circle going backwards (anticlockwise), so on a diagram we already know it's in the third quadrant of the circle (somewhere between pi and 3pi/2 rads).
We also know it is pi/3 away from pi, so we are looking at sqrt(3) or -sqrt(3) because of those exact values.
Now we just need to work out if it's positive or negative. You can look up a graph of tan and it'll show that the graph intercepts y at (0,0) and has a period of pi rads. Therefore between pi and 3pi/2 rads, the values of tan are positive. Therefore, this gives us our answer of sqrt(3).
1. Subtract 6 from both sides now you would get..
2z=-10
Now divide each side by 2z and you get
z= -5
So the answer is -5
To calculate distance between two points we use the distance formula sqrt((x2−x1)^2+(y2−y1)^2).
To start, we find the square of the distance between x1 and x2 and y1 and y2. The distance between x1 and x2, or 1 and 3, is 2. The distance between y1 and y2, or 3 and -4, is 7.
Now we square 2 and 7 and add them together to get 4 + 49 = 53.
The last thing we do to find the distance is take the square root of 53. 53 is not a perfect square and is also a prime number so our answer in simplest form is still sqrt53.<span />
Answer:
24
Step-by-step explanation:
let 'x' = number
x/2 - 2 = 10
add 2 to each side to get:
x/2 = 12
cross-multiply to get:
x = 24
Answer:
12
Step-by-step explanation:
Since, B is between A and C.
