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Angelina_Jolie [31]
3 years ago
5

R=2/3t +v...solve for t...thanks

Mathematics
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

Step-by-step explanation:

10ac-x/11=-3 solve for a

mote1985 [20]3 years ago
4 0
\dfrac{2}{3}t+v=r\ \ \ |subtract\ v\ from\ both\ sides\\\\\dfrac{2}{3}t=r-v\ \ \ \ |multiply\ both\ sides\ by\ \dfrac{3}{2}\\\\\boxed{t=\frac{3}{2}(r-v)}
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Given: circle k(O), m LM = 164°, m WK = 68°, m∠MLK = 65°. Find: m∠LMW
Musya8 [376]

Answer:

The measure of angle LMW is m\angle LMW=67\°

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of arc MW

we know that

The inscribed angle measures half that of the arc comprising

so

m\angle MLK=\frac{1}{2}[arc\ MW+arc\ WK]

substitute the given values

65\°=\frac{1}{2}[arc\ MW+68\°]

130\°=[arc\ MW+68\°]

arc\ MW=130\°-68\°=62\°

step 2

Find the measure of arc LK

we know that

arc\ LM+arc\ MW+arc\ WK+arc\ LK=360\° -----> by complete circle

substitute the given values

164\°+62\°+68\°+arc\ LK=360\°

294\°+arc\ LK=360\°

arc\ LK=360\°-294\°=66\°

step 3

Find the measure of angle LMW

we know that

The inscribed angle measures half that of the arc comprising

so

m\angle LMW=\frac{1}{2}[arc\ LK+arc\ WK]

substitute the given values

m\angle LMW=\frac{1}{2}[66\°+68\°]=67\°

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