The maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
<h3>Calculating Maximum speed</h3>
From the question, we are to determine how much greater the maximum walking speed of Giraffe is to that of Hippopotamus
From the give information,
The maximum walking speed, S, is given by
S = √gL
Where g = 32ft/sec
and L is the length of the animal's leg
Thus,
For a Giraffe with a leg length of 6 feet
S = √32×6
S = √192
S = 13.856 ft/sec
For a Hippopotamus with a leg length of 3 feet
S = √32×3
S = √96
S = 9.798 ft/sec
Now, we will determine how many times greater 13.856 is than 9.798
13.856/9.798 = 1.41
Hence, the maximum walking speed of the Giraffe is 1.41 times greater than the maximum walking speed of the Hippopotamus
Learn more on Calculating Speed here: brainly.com/question/15784810
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Answer:
$2147.85
Step-by-step explanation:
199.5*.5=99.75
199.5+99.75=299.25
299.25*.3=89.775
299.25-89.775=209.475
209.475*.04=8.279
209.475+8.379=217.854
The x values decrease by 12 and the y increase by 4.
Answer: (x-12, y+4)
Answer:
See below.
Step-by-step explanation:
a.
Divide the leading terms:
6x^4 / 2x^2 = 3x^2
3x2 is a parabola so the long run is
as x ---> +/- infinity r(x) ----> + infinity. (answer).
b.
10,000x^3 / 50 x^3
= 200.
So r(x) as a horizontal asymptote at y ( r(x)) = 200. (answer).
Answer:
c
Step-by-step explanation:
