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3 years ago

A computer simulation tossed a 10-faced die 5 times. How many possible outcomes exist?

1 answer:

8 0

The answer to the problem wherein a computer simulation tossed a 10-faced die 5 times and you have to compute for the possible outcomes is simple. The answer is 18,144, 000 possible outcomes (if it's a combination). I got this through simply getting the 10! (3,628,800) and multiplying it 5.

However, if order is important (permutation), the number of possible outcomes is is 30240.

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Kenji buys 3 yards of fabric for $7.47 then he realizes that he needs 2 more yards how much would the extra fabric cost

Andrew [12]

3 yards = $7.47
1 yard = $(7.47 ÷ 3) = $2.29
2 yards = $ (2.29 × 2) = $5.58
$ (7.47 + 5.58) = $ 13.05

8 0

4 years ago

Read 2 more answers

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?

Firlakuza [10]

Answer:

f(x) = -x² + 8x - 16

Step-by-step explanation:

4 0

3 years ago

You are making the kite shown at the right from

Anna71 [15]

Answer:

a. Side lengths of ΔBEX are;

BE = 15 ft.

EX = 12 ft.

BX = 9 ft.

b. Side lengths of XEFY are;

XY = 6 ft.

EX = 12 ft.

FY = 7.5 ft.

EF = 7.5 ft.

c. Side lengths of YFGZ are;

GZ = 6 ft.

FY = 7.5 ft.

YZ = 2 ft.

FG = 2.5 ft.

d. Side length of triangle ZGC

GZ = 6 ft.

GC = 10 ft.

ZC = 8 ft.

Step-by-step explanation:

The given parameters are;

XY : YZ : ZC is 3 : 1 : 4

The length of BC = 25 in.

The length of EB = 15 in.

Therefore, EC = √(BC² - EB²) = √(25² - 15²) = √400 = 20 in.

Given that EX║ YF║GZ, we have;

EF : FG : GC is 3 : 1 : 4 (Parallel lines cut segments in equal proportions)

Therefore;

EF = 20 × 3/(3 + 1 + 4) = 7.5 ft.

FG = 20×1/8 = 2.5 ft.

GC = 20×4/8 = 10 ft.

EC/EX = BC/EB

20/EX = 25/15

EX = 15×20/25 = 12 ft.

XC = √(EC² - EX²) = √(20² - 12²) = 16

XY : YZ : ZC is 3 : 1 : 4

Therefore;

XY = 16 × 3/8 = 6 ft.

YZ = 16 × 1/8 = 2 ft.

ZC = 16 × 4/8 = 8 ft.

GZ = √(GC² - ZC²) = √(10² - 8²) = 6

Area of triangle ΔZGC = 1/2×6×8 = 24 ft²

XB = BC - XC = 25 - 16 = 9 ft.

Area of ΔBEX = 1/2×9×12 = 54 ft²

a. Side lengths of ΔBEX are;

BE = 15 ft.

EX = 12 ft.

BX = 9 ft.

FY = √(FC² - YC²) = √((10 + 2.5)² - (8 + 2)²) = 7.5 ft.

Area of YFGZ = (GZ + FY)/2 × YZ = (6 + 7.5)/2 × 2 = 13.5 ft²

Area of YFGZ = 13.5 ft²

Area of XEFY = XY × (EX + FY)/2 = 6 × (12 + 7.5)/2 = 58.5 ft.²

b. Side lengths of XEFY are;

XY = 6 ft.

EX = 12 ft.

FY = 7.5 ft.

EF = 7.5 ft.

c. Side lengths of YFGZ are;

GZ = 6 ft.

FY = 7.5 ft.

YZ = 2 ft.

FG = 2.5 ft.

d. Side length of triangle ZGC

GZ = 6 ft.

GC = 10 ft.

ZC = 8 ft.

6 0

3 years ago

Read 2 more answers

For what value of the variable the value of the expression 4(5x–8) is 4 more than the value of the expression 2(4–x)?

iragen [17]

For x=2, the value of the expression 4(5x–8) is 4 more than the value of the expression 2(4–x)

Step-by-step explanation:

We have to convert the given statement in mathematical or algebraic form to get the value of x for which the given condition is true.

So,

The problem can be written as:

$4(5x-8) = 2(4-x)+4$

Applying distributive property

$20x-32 = 8-2x+4\\20x-32 = 12-2x\\$

Adding 32 on both sides

$20x-32+32 = 12-2x+32\\20x = 44-2x$

Adding 2x on both sides

$20x+2x = 44-2x+2x\\22x=44$

Dividing both sides by 22

$\frac{22x}{22} = \frac{44}{22}\\x = 2$

Hence,

For x=2, the value of the expression 4(5x–8) is 4 more than the value of the expression 2(4–x)

Keywords: Linear equation, variables

Learn more about linear equation at:

#LearnwithBrainly

3 0

3 years ago

6+9=?? a.1 b.15 c.16 d.410 PLEASE HELP WILL MARK BRAINIEST

ddd [48]

The correct answer is
b. 15

3 0

4 years ago

Read 2 more answers