In △JKL, _______ is the leg opposite ∠J and _______ is the leg adjacent to ∠J. segment LK; segment JK segment LK; segment JL seg
1 answer:
Answer:
n △JKL, segment KL is the leg opposite ∠J and segment KL is the leg adjacent to ∠J.
Step-by-step explanation:
Given
See attachment for
Required
Complete the blanks
From the question. we understand that is the point of reference.
From the attached figure of
Segment KL is opposite to
Segment JL is adjacent to
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Answer:
a) 30.726m/s and b) 5.5549s
Step-by-step explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that . This formula implies that
.
First, observer that .
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So,
Then, applying 1) we have that
So, Sam Whittingham’s time through the 200 m was 5.5549s.