In △JKL, _______ is the leg opposite ∠J and _______ is the leg adjacent to ∠J. segment LK; segment JK segment LK; segment JL seg
1 answer:
Answer:
n △JKL, segment KL is the leg opposite ∠J and segment KL is the leg adjacent to ∠J.
Step-by-step explanation:
Given
See attachment for
Required
Complete the blanks
From the question. we understand that is the point of reference.
From the attached figure of
Segment KL is opposite to
Segment JL is adjacent to
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ANSWER
The correct answer is C
EXPLANATION
The given triangle is a right triangle. Since two angles are equal, it is a right isosceles triangle.
This implies that, x=8 units.
Using Pythagoras Theorem,
This implies that:
Take positive square root,
The correct answer is C
Answer:
f(x) = {x-3 for x ≤ -1; -3x+14 for x > 5}
Step-by-step explanation:
To write the piecewise function, we can consider the pieces one at a time. For each, we need to define the domain, and the functional relation.
__
<h3>Left Piece</h3>The domain is the horizontal extent. It is shown as -∞ to -1, with -1 included.
The relation has a slope (rise/run) of +1, and would intersect the y-axis at -3 if it were extended.
The first piece can be written ...
f(x) = x-3 for x ≤ -1
__
<h3>Right Piece</h3>The domain is shown as 5 to ∞, with 5<em> not included</em>.
The relation is shown as having a slope (rise/run) of (-3)/(1) = -3. If extended, it would intersect the point (5, -1), so we can write the point-slope equation as ...
y -(-1) = -3(x -5)
y = -3x +15 -1 = -3x +14
The second piece can be written ...
f(x) = -3x +14 for x > 5
__
<h3>Whole function</h3>Putting these pieces together, we have ...
_____
<em>Additional comment</em>
Sometimes it is convenient to write inequalities in number-line order (using < or ≤ symbols). This gives a visual indication of where the variable stands in relation to the limit(s). Perhaps a more conventional way to write the domain for the second piece is, <em>x > 5</em>.