Answer:
Find the minimum or maximum value of the function g (I) = -3x^2 - 6x + 5. Describe the domain and range of the function, and where the function is increasing and decreasing. > -1 all real numbers The function The maximum value is I < 0 The domain is and the range is right of I left -1 is increasing to the of I= and decreasing to the 0 12 :: yo y0 :: 8 :: IS-1 :: -1 :: 0 :: I> 0 :: 1 :: 8 :: < 0 :: left :: all real numbers :: y -8 :: y < 8 :: y8
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
Note that cos315° = cos45° and sin315° = - sin45° and
cos45° = sin45° = 
= 
Hence
12(cos315° + isin315°)
= 12(cos45° - isin45°)
= 12( - i )
= 6
- 6i
Please: Use "^" to denote exponentiation: <span>2x^2 + 8x - 12 = 0
Reduce this by div. every term by 2: </span><span>x^2 + 4x - 6 = 0
Here a=1, b=4 and c = -6. Square half of b, obtaining (4/2)^2 = 4, and add, and then subtract, this 4 to x^2 + 4x - 6:
</span> x^2 + 4x +4 - 4 - 6 = 0. Rewrite the square as (x+2)^2, obtaining new equation
(x+2)^2 = 10. Take the sqrt of both sides: x+2 = plus or minus sqrt(10).
Finally, solve for x: x = -2 plus or minus sqrt(10).
The answer is
3x-4y=-24
y=mx+b
-4y=-3x-24
y=(3/4)x+(-24/-4)
y=(3/4)x+6
slope m=3/4
y =6
(4a + 6b) x (2a - 2b)
the answer would be 8a2 + 4ab - 12b2
