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Gelneren [198K]
3 years ago
12

Lee spends 5 hours a day working for a lawn company and 2 hours cleaning pools. He wrote this equation to represent the total nu

mber of hours he works in a day.
d = 5 + 2

Lee works 4 days each week.

Which equation would represent the total time Lee works in a week?

A.
d = 4 · (5 + 2)

B.
d = 4 + (5 + 2)

C.
d = 4 + (5 · 2)

D.
d = (4 · 5) + 2
Mathematics
1 answer:
alexira [117]3 years ago
4 0
A is the answer because he works 2 jobs cleaning pools and mowing lawns so you would add their times together and he works 4 days a week so you would take this and multiply it by the amount of hours he works.

If you need an answer to the answer would be he works a total of 28hrs over a four day period
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If y = x+2 were arranged to y= x+1, how would you graph the new function compare with the first one
Kobotan [32]
Hope I was able to help u
8 0
3 years ago
Ming throws a stone off a bridge into a river below.
AURORKA [14]

Answer:

1 seconds after being thrown, the stone reaches its max height

Step-by-step explanation:

The parabolic (quadratic) equation is:

h(x)=-5(x-1)^2+45

Lets expand this in the form ax^2+bx+c, so we have:

h(x)=-5(x-1)^2+45\\h(x)=-5(x^2-2x+1)+45\\h(x)=-5x^2+10x-5+45\\h(x)=-5x^2+10x+40

We can say the values of a,b, and c, now to be:

a = -5

b = 10

c = 40

The number of seconds at which the max would occur is given by the point, x, at:

x=-\frac{b}{2a}

We know a and b, let's find the seconds, x,

x=-\frac{b}{2a}=-\frac{10}{2(-5)}=-\frac{10}{-10}=--1=1

Hence,

1 seconds after being thrown, the stone reach its max height

6 0
4 years ago
Read 2 more answers
Suppose a ball is thrown upward to a height of h 0 meters. After each​ bounce, the ball rebounds to a fraction r of its previous
gladu [14]

Answer:

A)1st term:45

2nd term:48.75

3rd term:49.6875

4th term:49.921875

B) Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

Step-by-step explanation:

We are given;

h₀ = Initial height of the ball = 30

r = Rebound fraction = 0.25

a) The arithmetic sequence of bouncing balls is given by the following;

Sₙ=h₀+2h₀(r¹+r²+r³+r⁴.........rⁿ)

The first term of the sequence is;

S₁ = h₀ + 2h₀r¹

S₁ = 30 + (2 × 30 × 0.25)

S₁ = 45

The second term of the sequence is;

S₂ = h₀ + 2h₀(r¹+r²)

S₂ = 30 + (2 × 30 × (0.25 + 0.25²)) = 48.75

The third term of the sequence is;

S₃ = h₀ + 2h₀(r¹ + r² + r³) = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³)) = 49.6875

S₄ = h₀ + 2h₀(r¹ + r² + r³ + r⁴)

S₄ = 30 + (2 × 30 × (0.25 + 0.25² + 0.25³ + 0.25⁴)) = 49.921875

B) The general expression for the nth term of the sequence is;

Sₙ = h₀ + 2h₀((∞, n=1) Σrⁿ)

4 0
3 years ago
I’m stuck on this which one is correct ?
stepan [7]
The answer is c. Bcs A + B = 90 [ 35 + 55 = 90]
3 0
3 years ago
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Please help me!
sweet-ann [11.9K]

Answer:

bueh

Step-by-step explanation:

3 0
3 years ago
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