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UNO [17]
3 years ago
15

The owner of the theater where the ticket price for an adult is $10 and the ticket price for a child is $7 wants to make at leas

t $300 when a movie is shown. Choose the inequality that shows the numbers of tickets that must be sold.
A. 10x + 7y > 300
B. 10x + 7y < 300
C. 10x + 7y ≥ 300
D. 10x + 7y ≤ 300
Mathematics
2 answers:
makkiz [27]3 years ago
8 0
Pretty sure it’s A.
shusha [124]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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You have a recipe for coconut cookies. The recipe makes 20 cookies. You need 100 cookies for a bake sale. Increase the recipe pr
lozanna [386]

Answer:

repeat this 5 times

Your welcome

7 0
2 years ago
Help please!!<br> 1. What is the value of n?<br> 2.What is the value of n?
lana66690 [7]

Using the intersecting chord theorem:

15 x 2 = 5 x n

Simplify:

30 = 5n

Divide both sides by 5:

n = 30/5

n = 6 m



8 x n+8 = 16 x n+2

Simplify:

8n +64 = 16n +32

Subtract 8n from both sides:

64 = 8n +32

Subtract 32 from both sides:

32 = 8n

Divide both sides by 8:

n = 32 /8

n = 4

4 0
3 years ago
Read 2 more answers
Un futbolista ha metido 2/9 del número de goles marcados por su equipo y otro la
storchak [24]

Answer:

77 goles

Step-by-step explanation:

Un futbolista ha marcado 2/9 del número de goles marcados por su equipo.

Otro anotó una cuarta parte del resto.

El resto = 1 - 2/9

= 7/9

De ahí que otro futbolista anotó

= 1/4 de 7/9

= 7/36

Si los otros jugadores han marcado 45 goles

Tenemos que averiguar la fracción de goles que marcó el otro jugador

Deje que el número total de goles marcados por el equipo durante la temporada = 1

Por lo tanto:

1 - (2/9 + 7/36)

1 - (8 + 7/36)

1 - 15/36

1 - 5/12

= 7/12

¿Cuántos goles marcó el equipo a lo largo de la temporada?

El número total de goles que marcó ese equipo se calcula como:

7/12 × x = 45

Donde x = número total de goles

7x / 12 = 45

Cruz multiplicar

7x = 45 × 12

x = 45 × 12/7

x = 77,142857143

Aproximadamente = 77 goles

7 0
2 years ago
If JKLM is a rhombus, MK = 30, NL = 13, and mZMKL = 41°, find each measure.
oksian1 [2.3K]

Answer:

NK = 15

JL = 26

KL = 19.85

\angle JKM =49

\angle JML =41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

Step-by-step explanation:

Given

MK = 30

NL = 13

\angle MKL = 41

Solving (a): NK

MK is a diagonal and NK is half of the diagonal. So:

NK = \frac{1}{2} * MK

NK = \frac{1}{2} * 30

NK = 15

Solving (b): JL

JL is a diagonal, and it is twice of NL.

JL = 2 * NL

JL = 2 * 13

JL = 26

Solving (c): KL

To solve for KL, we consider triangle KNL where:

\angle KNL = 90

and

KL^2 = NL^2 + NK^2

KL^2 = 13^2 + 15^2

KL^2 = 394

KL = \sqrt{394

KL = 19.85

Solving (d - h):

To do this, we consider triangle JKN

\angle KNL = \angle LNM = \angle MNJ = \angle JNK = 90 -- diagonals bisect one another at right angle

Alternate interior angles are equal. So:

\angle MKL = \angle KMJ = \angle KJL = \angle JLM = 41

Similarly:

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 90 - 41

\angle MKJ = \angle KML = \angle MJL = \angle JLK = 49

So:

\angle JKM =49

\angle JML =41

\angle MLK = \angle MLJ + \angle JLK

\angle MLK = 49 + 41

\angle MLK = 90

\angle MNL =90

\angle KJL =41

5 0
2 years ago
tims math homework is on five consecutive pages in the math textbook, and the sum of those page numbers is 630. what is the page
Brrunno [24]

Answer:129

Step-by-step explanation:

630/5 is 126. Add 126, two numbers below it, and two above it. So, 124+125+126+127+128=630. The next page is 129

3 0
3 years ago
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