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3 years ago

Find all real zeros of the function f(x) = 12

1 answer:

4 0

This function has no zeros.

This is because f(x)=12, meaning no matter the x value, the y value is always 12. If the y value is always 12, it is never 0, and therefore has no zeros.

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A package of 6 pairs of insulated gloves costs $51.54. What is the unit price of the pairs of gloves ?

mafiozo [28]

Answer:

$8.59

Step-by-step explanation:

The unit price is just asking for what one pair of gloves cost.

$\$ 51.54 \div6=\$8.59$

∴The unit price of the pairs of gloves is $8.59

Hope this helps!

6 0

2 years ago

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What’s the question mark

nikitadnepr [17]

Answer:

? = 30

Step-by-step explanation:

If the triangles are similar, then the only way I see this working is the sides measuring 63 and 54 are corresponding. The sides measuring 56 and 48 are corresponding. That leaves the sides measuring 35 and ? corresponding.

Set up a proportion.

63/54 = 35/?

63? = 54 * 35

63? = 1890

? = 30

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3 years ago

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Figure GHTA below is a parallelogram. = 6 cm, = 8 cm, and the measure of = 60°. Find the area.

Kruka [31]

Answer:

multiply

Step-by-step explanation:

4 0

3 years ago

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Find the area of the shaded region

melamori03 [73]

LxW 5x5=25 If you know one side is five than the other side is 52 because they’re both equal its the radius compared to the diameter radius is five the diameter is 10

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3 years ago

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A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

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3 years ago

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