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just olya [345]
3 years ago
11

Find all real zeros of the function f(x) = 12

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
4 0
This function has no zeros.

This is because f(x)=12, meaning no matter the x value, the y value is always 12. If the y value is always 12, it is never 0, and therefore has no zeros.
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The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V
Nat2105 [25]

Corrected Question

The volume of air inside a rubber ball with radius r can be found using the function V(r) = four-thirds pi r cubed. What does V(5/7) represent?

Answer:

(B)the volume of the rubber ball when the radius equals five-sevenths feet

Step-by-step explanation:

The Volume of a sphere of radius r can be found using the formula:

V(r)=\dfrac43 \pi r^3

Therefore comparing the expression: V(\dfrac57)  with V(r):

Radius, r=\dfrac57

Thus, V(\dfrac57)  is the volume of a ball of radius \dfrac57 feet.

The correct option is B.

4 0
3 years ago
Read 2 more answers
PLS HELP ASAP WILL GIVE BRAINLEAST
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Answer:

32

Step-by-step explanation:

8 0
3 years ago
The number of cases of a new disease can be modeled by the quadratic regression equation y = –2x2 + 36x + 6, where x represents
nirvana33 [79]

Since x represents the year, year 15 will be 15 years.

Plug in "15" as your "x"

y = -2(15)^2 + 36(15) + 6

15^2 = 225 (Exponents come before multiplication)

y = -2(225) + 36(15) + 6

y = -450 + 540 + 6

y = 90 + 6

y = 96

<em>The answer is B</em>

3 0
3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
A number cube is rolled 3 times.
Alex73 [517]
6....................
3 0
3 years ago
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