Find all real zeros of the function f(x) = 12
1 answer:
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We know that
X²+y²=9 -------> X²+y²=3²
is the equation of a circle with center (0,0) and radius r=3 units
so
<span>the translation of four units to the right and three units down is equals to move the center (0,0)--------> (0+4,0-3)------> (4.-3)
the new center of the circle is (4,-3)
the new equation is
(x-4)</span>²+(y+3)²=3²
see the attached figure
X²+y²=9 -------> X²+y²=3²
is the equation of a circle with center (0,0) and radius r=3 units
so
<span>the translation of four units to the right and three units down is equals to move the center (0,0)--------> (0+4,0-3)------> (4.-3)
the new center of the circle is (4,-3)
the new equation is
(x-4)</span>²+(y+3)²=3²
see the attached figure
Answer:
<h2>W = 16</h2>Step-by-step explanation:
<h3>To find W raise each of the sides of the equation to the power 4 to make W stand alone
That's
<h3>We have
W = 2⁴
We have the final answer as
<h3>W = 16</h3>Hope this helps you