The answer is d. it isn’t an exact number
Answer:

Step-by-step explanation:
To solve for <em>CD</em>, we can create a right triangle.
Where <em>CD</em> becomes the hypotenuse.
The length of the base of the triangle is 9 units.
The length of the height of the triangle is 5 units.
Apply Pythagorean theorem to solve for the hypotenuse.




Answer:
The method we will use to solve applications with linear inequalities is very much like the one we used when we solved applications with equations. We will read the problem and make sure all the words are understood. Next, we will identify what we are looking for and assign a variable to represent it. We will restate the problem in one sentence to make it easy to translate into an inequality. Then, we will solve the inequality.
Step-by-step explanation:
The method we will use to solve applications with linear inequalities is very much like the one we used when we solved applications with equations. We will read the problem and make sure all the words are understood. Next, we will identify what we are looking for and assign a variable to represent it. We will restate the problem in one sentence to make it easy to translate into an inequality. Then, we will solve the inequality.
I think the answer is 151.
Answer:
F
Step-by-step explanation:
Using the properties of 45-45-90 triangles
8=x*sqrt(2)
4sqrt(2)=x