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4 years ago

6

What is the answer for -x/3> or equal to 5

1 answer:

Fiesta28 [93]4 years ago

5 0

To find the solution, you plot 5 as the y intercept. Now x has a slope of -1x/3 so you move down 1 and over 3. If it is the greater than sign has a line underneath it, you use a solid line.If there is no line, use a dotted line Since the arrow is pointing towards x, you will shape upwards because it is either greater or equal.

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3 years ago

Find the distance between the points.<br> (-3,2) and (0,2)<br> The distance is

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d=3

Step-by-step explanation:

by using distance formula

d=√(x2-x1)²+(y2-y1)²

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7 0

4 years ago

prove that if f is integrable on [a,b] and c is an element of [a,b], then changing the value of f at c does not change the fact

Neko [114]

Answer with Step-by-step explanation:

We are given that if f is integrable on [a,b].

c is an element which lie in the interval [a,b]

We have to prove that when we change the value of f at c then the value of f does not change on interval [a,b].

We know that limit property of an integral

$\int_{a}^{b}f dt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$

$\int_{a}^{b} fdt=f(b)-f(a)$ ....(Equation I)

Using above property of integral then we get

$\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b} fdt$ ......(Equation II)

Substitute equation I and equation II are equal

Then we get

$\int_{a}^{b}fdt= f(c)-f(a)+{f(b)-f(c)}$

$\int_{a}^{b}fdt=f(c)-f(a)+f(b)-f(c)=f(b)-f(a)$

$\int_{a}^{c}fdt+\int_{c}^{b}fdt=f(b)-f(a)$

Therefore, $\int_{a}^{b}fdt=\int_{a}^{c}fdt+\int_{c}^{b}fdt$ .

Hence, the value of function does not change after changing the value of function at c.

6 0

3 years ago