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3 years ago

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On Sunday, a local hamburger shop sold a combined total of 448 hamburgers and cheeseburgers. The number of cheeseburgers sold wa

s three times the
number of hamburgers sold. How many hamburgers were sold on Sunday?

1 answer:

diamong [38]3 years ago

8 0

Answer:

How many hamburgers were sold on Sunday?

336

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Please Help Me! I need to pass.

Andru [333]

42 is the answer

Explanation:
50% of 80 is half of 80 which is 40

Then you would add 40 with 5% of 40

What you would do then is 5% times 40 then you would change the 5% into a decimal which is 0.05 and multiply it by 40 , which would get u 2

Then you would add the price with tax
40+2 = 42

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3 years ago

(3squared)squared x(10cubed)squared

kiruha [24]

Hii :))

$\tt {(3 ^{2} )}^{2} \times {(10^{3}) }^{2} \\ \tt = (3 \times 3) ^{2} \times {(10 \times 10 \times 10)}^{2} \\ \tt \: = {9}^{2} \times 1000 ^{2} \\ \tt = (9 \times 9) \times (1000 \times 1000) \\ = \tt \: 81 \times 1000000 \\ = \boxed{\tt \: 81000000}$

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3 years ago

Read 2 more answers

HELP ASAP I'M FAILING AND I DON'T UNDERSTAND THIS

nirvana33 [79]

The intercept can be found when all other variables are equated to zero.
x-intercept when y = 0 and z = 0: 8x + 6*0 + 3*0 = 24 gives x = 3
y-intercept when x = 0 and z = 0: 8*0 + 6y + 3*0 = 24 gives y = 4
z-intercept when x = 0 and y = 0: 8*0 + 6*0 + 3z = 24 gives z = 8

The intercepts are (3, 0, 0), (0, 4, 0), and (0, 0, 8).

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3 years ago

Enter the simplified form of the complex fraction in the box.

Ket [755]

The problem is:

$\frac{\frac{3}{x}+\frac{1}{4}}{1+\frac{3}{x}}$

We now do L.C.M. of numerator and add, also do L.C.M. of denominator and add together:

$\frac{\frac{12+x}{4x}}{\frac{x+3}{x}}$

Dividing by a fraction is same as multiplying by its reciprocal, so we have:

$\frac{12+x}{4x} * \frac{x}{x+3} \\$

x cancels out, so can multiply and write:

$\frac{12+x}{4} * \frac{1}{x+3} \\=\frac{12+x}{4x+12}$

This is the simplified form.

ANSWER: $\frac{12+x}{4x+12}$

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3 years ago

How many real solutions does a quadratic equation have if its discriminant is negative?

kvasek [131]

Answer:

A

Step-by-step explanation:

Discriminant is given by

$D = b^{2} -4ac$

If it is negative then in quadratic formula the square root part becomes negative which makes the solution complex.

so there cannot be any real solution if the Discriminant is negative or less than 0 ,

The correct option for the given question is

A

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3 years ago