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Marta_Voda [28]
3 years ago
15

Noah wants to predict who will be selected as the sixth-grade treasurer for student council. Which of the following groups shoul

d Noah survey to make his prediction?
The first 100 students from an alphabetical list of the entire school
The first 100 students from an alphabetical list of sixth graders
One hundred random students from the entire school
One hundred random students from the sixth grade
Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
8 0

Answer:

d

Step-by-step explanation:

xenn [34]3 years ago
4 0
<span>D. One hundred random students from the sixth grade is the best choice given!
</span><span>
Reasons why the other answers and not good choices.
A. The first 100 students from an alphabetical list of the entire school, is incorrect because his only concern is the 6th graders, by including everyone he would negatively skew the data.
B. The first 100 students from an alphabetical list of sixth graders, is incorrect because its unfair to those with names starting later in the alphabet.
C. One hundred random students from the entire school </span>is is better but still incorrect because his only concern is the 6th graders, <span>by including everyone he would again negatively skew the data.</span>

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There are ten time slots for these appointments. For the first time slot, there are 15 different students that can fill the slot. Next appointment, there are only 14 possible students since we already saw one. This goes on and on, 15 x 14 x 13... for 10 different time slots. 


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Ivahew [28]

Answer:

Step-by-step explanation:

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Twice the difference of a number and 6
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7 0
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Read 2 more answers
What is the cube root of 27a^l2?<br>-3a4<br>-3a<br> 3a<br> 3a*​
GuDViN [60]

Answer:

3a^4

Step-by-step explanation:

What is the cube root of  27a^{12}? This is the question.

We can write:

\sqrt[3]{27a^{12}}

We will use the below property to simplify:

\sqrt[n]{a*b}=\sqrt[n]{a}  \sqrt[n]{b}

So, we have:

\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}

We will now use below property to further simplify:

\sqrt[n]{x} =x^{\frac{1}{n}}

Thus, we have:

\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}

We know power to the power rule:  (a^z)^b=a^{zb}

Now, we have:

3*(a^{12})^{\frac{1}{3}}\\=3*a^{\frac{12}{3}}\\=3a^4

This is the correct answer:  3a^4

4 0
3 years ago
I need this answered ASAP.
expeople1 [14]
The answer for this has to be B)45
6 0
3 years ago
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