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3 years ago

Jake is traveling 14 mph in his boat. After 5 hours, how far will he have traveled?

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

Speed x distance = 70

Luden [163]3 years ago

6 0

Answer: 70

Step-by-step explanation: 14 times 5 = 70

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Write 450 miles per 18 gallons as a unit rate (miles per gallon)

fenix001 [56]

Multiply them together

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3 years ago

Jeremy has 3 yards of ribbon to use for wrapping gifts he cuts the ribbon into pieces that are one fourth yard long how many pie

nordsb [41]

This answer is pretty simple.

Since there are 3 yards of ribbon, and you need to make ____ number of pieces with each 1/4 long

To do this you divide.

3 divided by 1/4

The answer is 12

8 0

3 years ago

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A taxi driver estimates that his earnings are $240 on a fine day and $320 on a wet day. What are his expected earnings on a day

castortr0y [4]

Probability of raining=0.45
Probability of not raining=1-0.45=0.55
The expected earning will be given by:
E(x)=240(0.55)+320(0.45)
E(x)=132+144
E(x)=276

Answer: $276

7 0

3 years ago

Set up the characteristic equation, which is given by r2 − 5r − 6 = 0. The roots of this equation are given by r1 = 6 and r2 = −

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

From your characteristic equation, your recursive equation is

$f(n+2) = 5 f(n=1) +6f(n)$

the general solution:

$f(n) = A6^n + B(-1)^n$

The initial conditions are

$f(0) =1 ~~~and~~~ f(1) = 3$

For f(0) = 1, that is

$f(0) = A6^0 + B(-1)^0 = A+ B=1 (*)$

For f(1) = 3, that is

$f(1) = A6^1 + B(-1)^1 = 3$

$6A- B = 3 (**)$

From (*) and (**) you solve for A and B

you have A = 4/7 and B= 3/7

Replace A, B into the general one, you have the particular solution for the given condition

$f(n) = 4/7 *6^n +3/7*(-1)^n$

4 0

4 years ago

At one vehicle inspection station, 13 of 52 trucks and 11 of 88 cars failed the emissions test. assuming these vehicles were rep

Leto [7]

The standard error (SE) of the sampling distribution difference between two proportions is given by:

$SE=\sqrt{p(1-p)\left(\frac{1}{n_1}+\frac{1}{n_2}\right)}$

where p is the pooled sample proportion, $n_1$ is the size of sample 1, and $n_2$ is the size of sample 2.

 $p= \frac{p_1n_1+p_2n_2}{n_1+n_2}$

Given that at one vehicle inspection station, 13 of 52 trucks and 11 of 88 cars failed the emissions test.

 $p_1= \frac{13}{52} =0.25 \\ \\ p_2= \frac{11}{88} =0.125 \\ \\ n_1=52 \\ \\ n_2=88 \\ \\ p= \frac{0.25(52)+0.125(88)}{52+88} \\ \\ = \frac{13+11}{140} = \frac{24}{140} =0.1714$

 $SE=\sqrt{0.1714(1-0.1714)\left(\frac{1}{52}+\frac{1}{88}\right)} \\ \\ = \sqrt{0.1714(0.8286)(0.0192+0.0114)} \\ \\ = \sqrt{0.1714(0.8386)(0.0306)} = \sqrt{0.0044} \\ \\ =0.0663$

5 0

4 years ago

Read 2 more answers