PLEASE SOMEONE ANSWER MY QUESTION
Procedure:
1) Integrate the function, from t =0 to t = 60 minutues to obtain the number of liters pumped out in the entire interval, and
2) Substract the result from the initial content of the tank (1000 liters).
Hands on:
Integral of (6 - 6e^-0.13t) dt ]from t =0 to t = 60 min =
= 6t + 6 e^-0.13t / 0.13 = 6t + 46.1538 e^-0.13t ] from t =0 to t = 60 min =
6*60 + 46.1538 e^(-0.13*60) - 0 - 46.1538 = 360 + 0.01891 - 46.1538 = 313.865 liters
2) 1000 liters - 313.865 liters = 613.135 liters
Answer: 613.135 liters
Answer:
D
Step-by-step explanation:
5/5 : 15/5
gives
1:3
......
Answer:
1. 10^(38)
2. total amount = 10^11 or total amount = $100000000000
Step-by-step explanation:
For every time that we multiply powers with the same base we maintain the base and sum the powers. Therefore we have:
1. (10^32)*(10^6)
10^(32 + 6)
10^(38)
2. If each of the 10^6 programmers make 10^5 then the total money they make together is the product of the number of programs with the sallary each makes. We have:
total = (10^6)*(10^5)
total = 10^(6 + 5)
total = 10^11
total = $100000000000
