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Daniel [21]
3 years ago
13

In a certain month, Oscar sells 6 cars more than Jackie. If together they sell 30 cars, how many cars did Jackie sell?

Mathematics
2 answers:
diamong [38]3 years ago
8 0

Answer:

Jackie sold 12 cars.

Step-by-step explanation:

If we call the number of cars Oscar sold O, and the number of cars Jackie sold J, we can say the following:

O = J + 6

As Oscar sold 6 cars more than Jackie.

Together, they sold 30 cars.

O + J = 30

Since we know that:

O = J + 6

... we can put this into our previous equation.

O + J = 30

(J + 6) + J = 30

J + J + 6 = 30

2 * J + 6 = 30

Subtract 6 from both sides:

2 * J = 24

Divide both sides by 2:

J = 24 / 2

J = 12

Jackie sold 12 cars.

inn [45]3 years ago
7 0

Answer:

12 cars

Step-by-step explanation:

Let Jackie sold x cars

So, no of cars sold by Oscar = x + 6

According to the given information:

Number of cars sold by Oscar and Jackie together = 30

\therefore \: (x + 6) + x = 30 \\ 2x + 6 = 30 \\ 2x = 30 - 6 \\ 2x = 24 \\ x =  \frac{24}{2}  \\ x = 12

Hence, Jackie sold 12 cars.

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