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Hitman42 [59]
2 years ago
14

Please help!!! asap! ( 10 points)

Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
3 0

Answer:

a. true: 3    false: -5

b. true: 9    false: 2

c. true: 1/3  false: 1

d. true: 2    false: 3

I hope this helps!

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Please give me correct answer​
bagirrra123 [75]

Answer:

7.a. 8.b, yan. po. ang. sagot

5 0
2 years ago
Jensen spends $18.00 for every 72 text messages she sends. How many messages can Jensen send for $1.00
Rasek [7]
4 texts because 18 dollars for 72 texts
can reduce to 1 dollar for 4 texts. i can try to explain further if needed
8 0
2 years ago
105159 rounded to the nearest 10 is
kicyunya [14]
The answer is 105160 because five or more up the score, four or less let it rest
6 0
3 years ago
Help pleaseee , don’t really know how to do this :)
yawa3891 [41]

Answer:

x= -p+q+y

Step-by-step explanation:

-x on each side

y-x=p-q

-y on each side

-x=p-q-y

÷everything on both sides by ‐1

We have to divide by -1 because x can't be negative

x = -p+q+y

I really hope this is right because I don't want to let you down.

-LampteyJ

8 0
3 years ago
From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once. What is the probability o
murzikaleks [220]

Answer:

0.13

Step-by-step explanation:

From a bag containing 5 nickels, 8 dimes, and 7 quarters, 5 coins are drawn at random and all at once

we need to select 2 nickels from 5 nickels and select 2 dimes from 8 dimes and 1 quarter from 7 quarters

There are total of 5+8+7=20 coins

select 5 coins from total of 20 coins

2 nickels can be selected from 5 nickels in 5C2 ways

5C2=\frac{5!}{2!(5-2)!} =\frac{5!}{2!(3!)!}=10

2 dimes selected from 8 dimes

8C2=\frac{8!}{2!(8-2)!} =\frac{6!}{2!(6!)}=28

1 quarter selected from 7 quarter

7C1=\frac{7!}{1!(7-1)!} =\frac{7!}{1!(6!)}=7

5 coins selected from 20 coins

20C5=\frac{20!}{5!(15)!} =15504

probability of getting 2 nickels, 2 dimes, and 1 quarter

\frac{10 \cdot 28 \cdot 7}{15504} =\frac{1960}{15504} =0.13

5 0
2 years ago
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