I: y<2*x
II: y<8
III: x>2
a: (5,3):
I: 3<2*5
3<10 ?yes
II: 3<8 ?yes
III: 5>2 ?yes
This is a solution
b: (6,0):
I: 0<2*6
0<12 ?yes
II: 0<8 ?yes
III: 6>2 ?yes
This is a solution
c: (3,3):
I: 3<2*3
3<6 ?yes
II: 3<8 ?yes
III: 3>2 ?yes
This is a solution
d: (1,-4):
I: -4<2*1
-4<2 ?yes
II: -4<8 ?yes
III: 1>2 ?no
This is not a solution
e: (4,-2):
I: -2<2*4
-2<8 ?yes
II: -2<8 ?yes
III: 4>2 ?yes
This is a solution
f: (5,9):
I: 9<2*5
9<10 ?yes
II: 9<8 ?no
This is not a solution
so a,b,c,e are solutions and d,f not
5x-7y=14
-5x -5x
^
Subtract 5x from both sides
-7y=-5x+14
Divide by -7 by all of the numbers
y=-5/7x-2
Answer:
Juan travel 31.4 feet farther than Fred in one rotation.
Step-by-step explanation:
In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:
(Eq. 1)
Where:
- Radius, measured in feet.
- Angular arch, measured in radians.
- Change in linear position, measured in feet.
If both makes one rotation in the carousel, we obtain the change in linear position of each player:
Fred (
, 
)
Juan (
, )
And the difference between both travelled distances is:
Juan travel 31.4 feet farther than Fred in one rotation.
