Let x be a random variable representing the length of a text messaging conversation, then
P(x > 3) = 1 - P(x < 3) = 1 - P(z < (3 - 2)/0.5) = 1 - P(z < 2) = 1 - 0.97725 = 0.02275
42% of the body voted = 11960
Total student body = 11960/42% = 28476.19 = 28476 students
Answer:
0.77 or 77%
Step-by-step explanation:
Given:
Percentage of brown peanuts = 12%
Percentage of yellow peanuts = 15%
Percentage of red peanuts = 12%
Percentage of blue peanuts = 23%
Percentage of orange peanuts = 23%
Percentage of green peanuts = 15%
Total = 0.12 + 0.15 + 0.12 + 0.23 + 0.23 + 0.15 = 1
Probability that a randomly selected peanut M&M is not orange:
P(orange)' = 1 - P(orange)
Where,
P(orange) = 23% = 0.23
Thus,
P(orange)' = 1 - 0.23
P(orange) ' = 0.77
Probability that a randomly selected peanut is not orange = 0.77
