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ratelena [41]
4 years ago
9

PLEASE HELP

Mathematics
1 answer:
lana66690 [7]4 years ago
4 0

Answer:

A. 38

Step-by-step explanation:

Let d = number of dimes.

Let n = number of nickels.

First equation:

There are twice as many dimes as nickels. The number of dimes is 2 times the number of nickels. The first equation is:

<em>d = 2n</em>

Second equation:

The value of a dime is $0.10. The value of a nickel is $0.05. The value of d number of dimes is 0.1d. The value of n number of nickels is 0.05n. The total value of d dimes and n nickels is 0.1d + 0.05n. We are told the total value of her dimes and nickels is $4.75. That gives us the second equation:

<em>0.1d + 0.05n = 4.75</em>

We have two equations and two unknowns, so we can answer this question by solving a system of two equations in two unknowns.

d = 2n

0.1d + 0.05n = 4.75

We will use the substitution method.

Since d = 2n, replace d in the second equation with 2n.

0.1(2n) + 0.05n = 4.75

0.2n + 0.05n = 4.75

0.25n = 4.75

n = 4.75/0.25

n = 19

Now that we know the number of nickels, we use the equation d = 2n to find the number of dimes.

d = 2n

d = 2 * 19

d = 38

Answer: Debra had 38 dimes.

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Read 2 more answers
One-fourth of the residents of a particular community leave their garage doors unlocked when they go out to do an errand. The lo
Inessa [10]

Answer:

Required Probability = 0.625

Step-by-step explanation:

Given,

Probability of unlocked doors, P(U) = 0.25

Probability of locked doors, P(U') = 0.75

Probability of something being stolen when door is unlocked, P(S/U) = 0.05

Probability of something not being stolen when door is unlocked, P(S'/U) = 0.95

Probability of something being stolen when door is locked, P(S/U') = 0.01

Probability of something not being stolen when door is locked, P(S'/U') = 0.99\

probability of being stolen either door is locked or not,

P(S) =P(S/U).P(U) + P(S\U').P(U')

       = 0.05 x 0.25 + 0.95 x 0.75

       = 0.0125 + 0.0075

       = 0.02

Probability that door was unlocked when while steeling can by given by

P(U/S)\ =\ \dfrac{P(S/U).P(U)}{P(S)}

            =\ \dfrac{0.05\times 0.25}{0.02}

            = 0.625

hence, the required probability is 0.625.  

7 0
3 years ago
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