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SCORPION-xisa [38]
3 years ago
5

Write the equation of a line that passes through (2,6) and (-2,2)

Mathematics
1 answer:
Viktor [21]3 years ago
5 0

Answer:

y = x + 4

Step-by-step explanation:

The equation of the line is

y = mx + c

Step 1: find the slope

m = y2 - y1 / x2 - x1

Give points

( 2 , 6) ( -2 ,2)

x1 = 2

y1 = 6

x2 = -2

y2 = 2

m = 2 - 6 / -2 - 2

m = -4 / -4

m = 1

y = mx + c

y = 1x + c

y = x + c

Step 2: sub any of the two points given into the equation

( 2 , 6)

x = 2

y = 6

y = x + c

6 = 2 + c

6 - 2 = c

c = 4

Step 3: sub c into the equation

y = x + 4

The equation of the line is

y = x + 4

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2 years ago
RS= 4y+2, ST = 3y+8, and RT = 38 what is the value of y
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RS= 4y+2, ST = 3y+8, and RT = 38

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