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exis [7]
3 years ago
13

What is the length of the altitude of the equilateral triangle below?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0

we are given

equilateral triangle

we can see that triangle ACD is a right angled triangle

so, we can use Pythagoras theorem for this triangle

hypotenuse=AC

Adjacent=CD

opposite=AD=a

and

AC=6\sqrt{3}

CD=3\sqrt{3}

AD=a

now, we can use Pythagoras theorem

and we get

AC^2=CD^2+AD^2

now, we can plug values

(6\sqrt{3} )^2=(3\sqrt{3} )^2+a^2

now, we can solve for a

108=27+a^2

27+a^2-27=108-27

a^2=81

a=9

so, option-A..........Answer

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Answer:

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Step-by-step explanation:

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Find the cos A and tan B to four decimal places. URGENT
Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

<u>Pythagoras theorem</u>

hypotenuse^{2} = adjacent^{2} + opposite^{2}

hypotenuse^{2} = 8^{2} + 5^{2}

hypotenuse^{2} = 64 + 25

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hypotenuse = 9.4

a) Cos A

<u>Data:</u>

Adjacent = 8

Hypotenuse = 9.4

<u>Formula:</u>

Cos (Angle) = \frac{adjacent}{hypotenuse}

Cos A =  \frac{8}{9.4}

Cos A = 0.8511

A = cos^{-1} (0.8511)

A = 31.7°

b) Tan B

<u>Data: </u>

Opposite = 8

Adjacent = 5

<u>Formula:</u>

Tan (Angle) = \frac{opposite}{adjacent}

Tan B = \frac{8}{5}

Tan B = 1.6

B =  cos^{-1} (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

  • brainly.com/question/5013374
  • brainly.com/question/9532142

#LearnwithBrainly

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