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exis [7]
3 years ago
13

What is the length of the altitude of the equilateral triangle below?

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
7 0

we are given

equilateral triangle

we can see that triangle ACD is a right angled triangle

so, we can use Pythagoras theorem for this triangle

hypotenuse=AC

Adjacent=CD

opposite=AD=a

and

AC=6\sqrt{3}

CD=3\sqrt{3}

AD=a

now, we can use Pythagoras theorem

and we get

AC^2=CD^2+AD^2

now, we can plug values

(6\sqrt{3} )^2=(3\sqrt{3} )^2+a^2

now, we can solve for a

108=27+a^2

27+a^2-27=108-27

a^2=81

a=9

so, option-A..........Answer

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-4(x+1)-3=-3(x-4) solve for x please. Giving brainliest
Sophie [7]

Answer:

-19 = x

Step-by-step explanation:

Step 1: Write equation

-4(x + 1) - 3 = -3(x - 4)

Step 2: Solve for <em>x</em>

<u>Distribute:</u> -4x - 4 - 3 = -3x + 12

<u>Combine like terms:</u> -4x - 7 = -3x + 12

<u>Add 4x on both sides:</u> -7 = x + 12

<u>Subtract 12 on both sides:</u> -19 = x

4 0
3 years ago
Read 2 more answers
In circle P, EG and FH are diameters.<br> What is m EH?
zvonat [6]

Answer:

m(\widehat{EH}) = 130°

Step-by-step explanation:

Angles subtended at the center by the arcs (\widehat{HG}) and (\widehat{EF}) are ∠HPG and  ∠EPF.

Since these angles are the vertical angles both will be equal.

m∠HPG ≅ m∠EPF

3x - 10 = 2x + 10

3x - 2x = 10 + 10

x = 20

Therefore, m(\widehat{HG})=(3\times 20) - 10

                               = 50°

Similarly m(\widehat{EF}) = 50°

In the same way angles subtended at the center will be equal.

m∠EPH ≅ m∠FPG

and m(\widehat{EH})=m(\widehat{FG})

Since m(\widehat{EH})+m(\widehat{FG})+m(\widehat{EF})+m(\widehat{HG})=360°

m(\widehat{EH})+m(\widehat{EH})+50+50=360

2m(\widehat{EH})=360-100

m(\widehat{EH})=130

Therefore, measure of arc EH = 130°

3 0
3 years ago
What is the sum of a geometric sequence 1,3,9,... if there are 14 terms
Maksim231197 [3]
1, 3, 9, 27, 81, 243, 729, 2187, 6561, 19683, 59049, 177147, 531441, 1594323.
If this is the proper sequence pattern, we add up all the numbers to get a sum.
The total sum is 2391457.
7 0
3 years ago
In circle L, points E and F lie on the circle such that E, F and L are not collinear. If LE, LF and EF are drawn then which of t
frozen [14]

Answer:

<u>option (2) it is and isosceles triangle. </u>

Step-by-step explanation:

In circle L, points E and F lie on the circle such that E, F and L are not collinear

If LE, LF and EF are drawn

So, LE = EF = the radius of the circle L

So, LEF is an isosceles triangle.

The answer is option (2) it is and isosceles triangle.

8 0
3 years ago
Find the missing term and the missing coefficient 6a −( )5a =( ) a2 − 35a
andrew11 [14]
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
 Let the missing term be X
 Let the missing coefficient be Y
 Therefore, (6a – X)5a = Y(a^2) – 35a
 6a x 5a – X.5a = Y.a^2 – 35a
 30a^2 – X.5a = Y.a^2 – 35a
  Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
 30 = Y; 5X = 35
Y = 30; X = 7
   Therefore, (6a-7)5a = 30 a^2 – 35a <span>
</span>
3 0
3 years ago
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