For the angle MPN we know that is oposite to the angle QPL so the will be equal so:

Now with the value of MPN we can made an equation for x so:

and we solve for x

and the angle LPM will be the complementari angle of 125 so:
Answer:
2/10-4/10x
Step-by-step explanation:
Answer: P(x)= x³ - 3 x² - 46 x +168
Step-by-step explanation:
(4,6, -7)
hence the polynomial will be equal to
P(x) = (x-4) (x-6) (x+7)
P(x) = (x-4) (x²+7 x -6 x -42)
P(x) = (x-4) (x²+x -42)
P(x) = x³ + x²-42 x -4 x² -4 x +168
P(x) = x³ - 3 x² - 46 x +168
hence, the required polynomial is P(x) = x³ - 3 x² - 46 x +168
<h2>Have a awesome day✨</h2>
The area of the shaded sector must be 144π units².
<h3>What is the area of the circle?</h3>
The area of the circle is defined as the product of the pie and the square of the radius.
The area of the circle = 
We know that the angle measurement of central angle QRS is less than π radians.
for r = 18 units
The area of the circle = π18² = 324π units²
The area of the half of a circle = 324π /2 = 162π units²
The area of a quarter of a circle = 324π /4 = 81π units²
so
The area of the shaded sector < 162π units²
and
The area of the shaded sector > 81π units²
Hence the answer must be 144π units²
Learn more about angles;
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