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2 years ago

1. Find the perimeter. 13 yd 14 yd 7 yd 18 yd

Mathematics

2 answers:

nikdorinn [45]2 years ago

4 0

Answer:

52 yards

Step-by-step explanation:

Perimeter is all sides added together.

13 + 14 + 7 + 18 = 52

Pie2 years ago

3 0

The answer is 52! :)

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Keanu and Jeremy sold 25 boxes of popcorn for fundraiser Tiana so 60% of the boxes how many boxes did each cell

Simora [160]

Answer:

Tiana sold 15 boxes and Jeremy and Keanu sold 10

Step-by-step explanation:

60% of 25 = 15

25 - 15 is 10

This is the way I understand the problem.

7 0

2 years ago

A city's population is 12,000 and grows at 2.6% rate. What will the population be after 25 years? A city's population is 230,000

Levart [38]

Answer:

The 12000 City would become 22,986 people, while the 230,000 city would become a population of 124,223.

Step-by-step explanation:

1st Part:

=12000⋅(0.026000000000000002⋅25)

=12000(2.718281828459045)(0.65)

=22986

2nd Part:

=230000⋅(−0.044000000000000004⋅14)

=230000(2.718281828459045)(−0.616)

=124223

3 0

2 years ago

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RideAnS [48]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Someone pls help and show ur work

ale4655 [162]

Answer:

8x8=16

easy

https://youtu.be/WYNfQabLpuk

6 0

2 years ago

Evaluate the surface integral:S

rjkz [21]

Assuming $S$ does not include the plane $z=0$ , we can parameterize the region in spherical coordinates using

$\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle$

where $0\le u\le2\pi$ and $0\le v\le\dfrac\pi/2$ . We then have

$x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v$
$(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v$

Then the surface integral is equivalent to

$\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du$

We have

$\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle$
$\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle3\cos u\cos v,3\sin u\cos v,-3\sin v\rangle$
$\implies\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}=\langle-9\cos u\sin^2v,-9\sin u\sin^2v,-9\cos v\sin v\rangle$
$\implies\left\|\dfrac{\partial\mathbf r(u,v)}{\partial u}\times\dfrac{\partial\mathbf r(u,v)}{\partial v}\|=9\sin v$

So the surface integral is equivalent to

$\displaystyle243\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv\,\mathrm du$
$=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv$
$=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw$

where $w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv$ .

$=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}$
$=\dfrac{243}2\pi$

4 0

2 years ago