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2 years ago

Discuss the different kinds of real numbers. In your answer

Mathematics

1 answer:

zubka84 [21]2 years ago

5 0

Answer:

Real numbers are mainly classified into rational and irrational numbers. Rational numbers include all integers and fractions. All negative integers and whole numbers make up the set of integers. Whole numbers comprise of all natural numbers and zero.

Step-by-step explanation:

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In July, the average temperature in one US city was 29 degrees by December, the average temperature had fallen by 29 degrees. Ex

VikaD [51]

Step-by-step explanation:

In July, it was positive 29 degrees, but in December it was negative 29 degrees. When you have 29-29 you get 0. Hope that helped

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Curtis bought 4 DVDs that each cost the same amount. He had a $10-off coupon and spent $46 in all. What was the cost of each DVD

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3 years ago

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emmainna [20.7K]

Answer:

D (0, 2)

General Formulas and Concepts:

Algebra I

The y-intercept is the y value when x = 0. Another way to reword that is when the graph crosses the y-axis.

Slope-Intercept Form: y = mx + b

m - slope
b - y-intercept

Step-by-step explanation:

Step 1: Define

y = 3/4x + 2

Step 2: Break Function

Identify Parts

Slope m = 3/4

y-intercept b = 2

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2 years ago

Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?

photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

$D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6$

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

$T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326$

What is the probability that they are both queens?

$P = \frac{D}{T} = \frac{6}{1326} = 0.0045$

0.45% probability that they are both queens.

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3 years ago