Just move the decimal twice to the right. So 11%
3pi/7 < pi/2 because 3/7 < 1/2, and pi/2 is a right angle. Conclusion: the angle opposite side a is an acute angle. In this situation the triangle could be a right triangle, in which case C would be true, but it does not have to be a right triangle, so don´t choose C. Similarly, it could be an acute triangle, in which case B would be true, but it does not have to be, so don´t choose B. Also, A says the angle opposite side a is obtuse, which is false. So don´t choose A. That leaves D, which says the angle opposite side a is acute, which we know is true. So the answer is <span>D. b^2 + c^2 > a^2</span>
X's cancel 5y = 20 y= 4 X=0
You have written 0 = 4x.
The value of x that makes it true is x = 0, given that 4 times 0 is 0.
Nevertheless, I think you wanted to write 0 = 4 ^x (this is 4 raised to the power 4).
In that case, there is not any valued of x that satisfies the equation. This is, the equation is always false.
That is because, there is not any value of x for which 4^x is zero. The range of this function is al the positive values of x, which exclude zero.
