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3 years ago

Which of the following statements regarding immunization are true?

Mathematics

1 answer:

DochEvi [55]3 years ago

8 0

Answer:

B. II only

Step-by-step explanation:

Immunisation is used to lower the risk factor that may arise due to change in interest rate . For it, cash inflow and cash outflow are matched in terms of their timing . In other words, effective duration of asset and liability are matched with the help of methods like cash flow matching , duration matching etc.

Even lowering of interest rate in long term may entail risk because it may increase the bond price which may affect the business adversely in some way if bond is kept as liability . It may reduce the price of asset if it is held as asset .

Exact matching is possible only when matching of cash flow is achieved along with its timing . Matching of present value will not serve the purpose .

Macaulay or modified duration can be used to develop an immunization strategy . Both of them calculate the duration of asset and liability with some change in the method of calculation.

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3 0

1 year ago

what is the volume of a triangular pyramid that is 10 inches tall and has a base area of 9 square inches please help

andreyandreev [35.5K]

Answer:

90 but since its a triangle but im

pretty sure you have to divide by 2 so 45 i think

3 0

3 years ago

In AJKL, JL is extended through point L to point M, m m

arlik [135]

Answer:

x = 15

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ KLM is an external angle of the triangle, thus

∠ KLM = ∠ JKL + ∠ KJL , substitute values

5x - 7 = x + 20 + 2x + 3

5x - 7 = 3x + 23 ( subtract 3x from both sides )

2x - 7 = 23 ( add 7 to both sides )

2x = 30 ( divide both sides by 2 )

x = 15

4 0

2 years ago

Use any of the methods to determine whether the series converges or diverges. Give reasons for your answer.

Aleks [24]

Answer:

It means $\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$ also converges.

Step-by-step explanation:

The actual Series is::

$\sum_{n=1}^\inf} = \frac{7n^2-4n+3}{12+2n^6}$

The method we are going to use is comparison method:

According to comparison method, we have:

$\sum_{n=1}^{inf}a_n\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n$

If series one converges, the second converges and if second diverges series, one diverges

Now Simplify the given series:

Taking"n^2"common from numerator and "n^6"from denominator.

$=\frac{n^2[7-\frac{4}{n}+\frac{3}{n^2}]}{n^6[\frac{12}{n^6}+2]} \\\\=\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{n^4[\frac{12}{n^6}+2]}$

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\ \ \ \ \ \ \ \ \sum_{n=1}^{inf}b_n=\sum_{n=1}^{inf} \frac{1}{n^4}$

Now:

$\sum_{n=1}^{inf}a_n=\sum_{n=1}^{inf}\frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\ \\\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{[7-\frac{4}{n}+\frac{3}{n^2}]}{[\frac{12}{n^6}+2]}\\=\frac{7-\frac{4}{inf}+\frac{3}{inf}}{\frac{12}{inf}+2}\\\\=\frac{7}{2}$