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xxTIMURxx [149]
3 years ago
7

Peter went to Fury's Heavyweight Buffet for lunch. The total cost of Peter's meal can be represented by the expression $0.25z +

$3.00d, where $0.25 is the price per ounce and the drinks cost $3. How much does Peter's lunch cost if he got 3 pounds of food (48 ounces) and one drink?
A$12
B$15
C$9.25
D$48
Mathematics
1 answer:
ollegr [7]3 years ago
3 0

Answer:

B

Step-by-step explanation:

0.25z+3d

=0.25(48)+3

=12+3

=15$

Brainliets please

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Name 3 pairs of adjacent angles and 3 pairs of vertical angles.​
Scrat [10]

Hey there!

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8 0
3 years ago
What do you call -6 and 6 or 3 and -3
myrzilka [38]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
Geoffery went on a trip across South America. He took 1,750 US dollars (USD) with him. In Chile, he traded his money for Chilean
AURORKA [14]
To calculate, 1st convert <span>1,750 USD to CLP by multiplying it with exchange rate 496.50 CLP/1USD. Total is CLP 868,875. Then by subtracting the expenses in CLP (CLP 217,513), remaining is CLP 651,362. Convert it to VEF by multiplying the exchange rate 0.1283 VEF/1 CLP. Resulting is </span><span> VEF 83,569.74. Then, subtract it with the expenses in VEF (VEF 31,422.19). Remaining VEF is </span><span> VEF 45,147.55. Next, convert it to PYG by multiplying it with 1,063.95 PYG/1 VEF. Result is </span><span> PYG 48,034,740.72. Next, subtract it with the expenses in PYG (PYG </span>12,857,441.39). Difference is PYG 35,177,299.33. Lastly, convert if to USD by multiplying it with 0.00002186 USD/1 PYG. Final answer is <span> USD <span>768.98.</span></span>
3 0
2 years ago
Read 2 more answers
Simplify the expression to a polynomial in standard form: (4x-3)(-2x^2-7x-5)
Brums [2.3K]

How to solve your problem

(4−3)(−22−7−5)

(4x−3)(−2x2−7x−5)(4x-3)(-2x^{2}-7x-5)(4x−3)(−2x2−7x−5)

Simplify

1

Distribute

(4−3)(−22−7−5)

(4x−3)(−2x2−7x−5){\color{#c92786}{(4x-3)(-2x^{2}-7x-5)}}(4x−3)(−2x2−7x−5)

4(−22−7−5)−3(−22−7−5)

2

distribute

4(−22−7−5)−3(−22−7−5)

4x(−2x2−7x−5)−3(−2x2−7x−5){\color{#c92786}{4x(-2x^{2}-7x-5)}}-3(-2x^{2}-7x-5)4x(−2x2−7x−5)−3(−2x2−7x−5)

−83−282−20−3(−22−7−5)

3

−83−282−20−3(−22−7−5)

−8x3−28x2−20x−3(−2x2−7x−5)-8x^{3}-28x^{2}-20x{\color{#c92786}{-3(-2x^{2}-7x-5)}}−8x3−28x2−20x−3(−2x2−7x−5)

−83−282−20+62+21+15

4

Solution

−83−222++15

I know this looks like a lot but its just how you solve your problem.

therefor, your answer is

Solution

−83−222++15

<em>Hope this helps!</em>

<em>Have a great day!</em>

<em>-Hailey</em>

6 0
3 years ago
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