Answer:
A. True
B. True
C. False
D. False
Explanation:
Electrons travel around the nucleus in circular orbits and moves from one orbit to another orbit when they absorb energy or lose energy. The Bohr atom is the model currently accepted for electrons in atoms because this model provides the right information about presence of electrons around the orbits. Scientists know the energies of electrons as well as the areas (orbitals) where the electrons are probably located with the help of new technology.
Hello!
the correct setup is shown at bottom of your question
we get
total moles*(1/102.0 g/mol)= total grams Al2O3
hope this helps. any questions please ask. thank you kindly
Answer: 11.02 moles of Ag can be formed.
Explanation:
To calculate the moles :
The balanced chemical equation is:
According to stoichiometry :
1 moles of
produces = 2 moles of
Thus 5.51 moles of
will produce=
of
Thus 11.02 moles of Ag can be formed.
Answer:

Explanation:
We must use the Nernst equation

The equation for the cell reaction is is
2Cl⁻(0.384 mol·L⁻¹) + 2Co³⁺(0.324 mol·L⁻¹) ⇌ Cl₂(5.80 atm) + 2Co²⁺(0.158 mol/L)
Data:
E° = 0.483 V
R = 8.314 J·K⁻¹mol⁻¹
T = 25 °C
n = 2
F = 96 485 C/mol
Calculation:
T = 25 + 273.15 = 298.15 K
![Q = \dfrac{\text{[Cl}^{-}]^{2}[\text{Co}^{3+}]^{2}}{p_{\text{Cl}_{2}}^{2}\text{[Co}^{3+}]^{2}} = \dfrac{0.384^{2} \times 0.324^{2}}{5.80 \times 0.158^{2}} =0.1069\\\\E = 0.483 - \left (\dfrac{8.314 \times 298.15 }{2 \times 96485}\right ) \ln(0.1069)\\\\=0.483 -0.01285 \times (-2.236) = 0.483 + 0.02872 = \textbf{0.512 V}\\\text{The cell potential is } \large\boxed{\textbf{0.512 V}}](https://tex.z-dn.net/?f=Q%20%3D%20%5Cdfrac%7B%5Ctext%7B%5BCl%7D%5E%7B-%7D%5D%5E%7B2%7D%5B%5Ctext%7BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%7Bp_%7B%5Ctext%7BCl%7D_%7B2%7D%7D%5E%7B2%7D%5Ctext%7B%5BCo%7D%5E%7B3%2B%7D%5D%5E%7B2%7D%7D%20%3D%20%5Cdfrac%7B0.384%5E%7B2%7D%20%5Ctimes%200.324%5E%7B2%7D%7D%7B5.80%20%5Ctimes%200.158%5E%7B2%7D%7D%20%3D0.1069%5C%5C%5C%5CE%20%3D%200.483%20-%20%5Cleft%20%28%5Cdfrac%7B8.314%20%5Ctimes%20298.15%20%7D%7B2%20%5Ctimes%2096485%7D%5Cright%20%29%20%5Cln%280.1069%29%5C%5C%5C%5C%3D0.483%20-0.01285%20%5Ctimes%20%28-2.236%29%20%3D%200.483%20%2B%200.02872%20%3D%20%5Ctextbf%7B0.512%20V%7D%5C%5C%5Ctext%7BThe%20cell%20potential%20is%20%7D%20%5Clarge%5Cboxed%7B%5Ctextbf%7B0.512%20V%7D%7D)