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elena-14-01-66 [18.8K]
3 years ago
8

The temperature of an object is directly related to A. the volume of the object. B. the motion of its particles. C. the potentia

l energy of its chemical bonds. D. the mass of the object.
Chemistry
2 answers:
DiKsa [7]3 years ago
5 0
I think its B good luck :)
Afina-wow [57]3 years ago
4 0

Answer: Option (B) is the correct answer.

Explanation:

In a solid object, molecules are closely packed together due to strong intermolecular forces between them. So, when heat is provided to the object then forces between the atoms decreases and as a result, atoms start to move from their initial place.

Hence, atoms gain kinetic energy due to increase in their motion.

For example, when ice is heated it changes into liquid state of water.

Also, K.E = \frac{3}{2}kT

where     k = Boltzmann constant

              T = temperature

Hence, kinetic energy is directly proportional to temperature.

Thus, we can conclude that the temperature of an object is directly related to the motion of its particles.

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How does an electron reach an excited state
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When an electron quickly occupies an strength state increased than its ground state, it is in an excited state. An electron can end up excited if it is given greater energy, such as if it absorbs a photon, or packet of light, or collides with a close by atom or particle.

5 0
3 years ago
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Suppose you are working with a NaOH stock solution but you need a solution with a lower concentration for your experiment. Calcu
Svet_ta [14]

Answer:

V_1=23.3~mL

Explanation:

In this case, we have a dilution problem. We have to remember that in the dilution procedure we go from a solution with higher concentration to a solution with lesser concentration. Therefore we have to start with the dilution equation:

C_1*V_1=C_2*V_2

Now we can identify the variables:

C_1=~1.475_M

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C_2=~0.1374_M

V_2=~250.0~mL

If we plug all the values into the equation:

1.475_M*V_1=0.1374_M*250.0~mL

And we solve for V_1:

V_1=\frac{0.1374_M*250.0~mL}{1.475_M}

V_1=23.3~mL

I hope it helps!

8 0
3 years ago
A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.314 kg of water?
Mariulka [41]

Answer:

g NaCl = 424.623 g

Explanation:

<em>C</em> NaCl = 3.140 m = 3.140 mol NaCl / Kg solvent

∴ solvent: H2O

∴ mass H2O = 2.314 Kg

mol NaCl:

⇒ mol NaCl = (3.140 mol NaCl/Kg H2O)×(2.314 Kg H2O) = 7.266 mol NaCl

∴ mm NaCl = 58.44 g/mol

⇒ g NaCl = (7.266 mol NaCl)×(58.44 g/mol) = 424.623 g NaCl

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3 years ago
PLEASE ANSWER AS SOON AS POSSIBLE! 25 Pts
vovikov84 [41]

Um Is there a picture :/

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3 years ago
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