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BabaBlast [244]
2 years ago
15

Simplify. (y3)5 · y4

Mathematics
2 answers:
ICE Princess25 [194]2 years ago
8 0

y^3 * 5 * y^4

= 5y^(3+4)

= 5y^7 answer

lyudmila [28]2 years ago
8 0

(y3)^5 · y4

= y^(3*5) · y4

= y^15 · y4

= y^(15 + 4)

= y^19

Hope that helps.

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Find an equation in standard form of the parabola passing through the points (1, -2), (2,-2), (3,-4)
Yuliya22 [10]
The standard form of a parabola is y=ax²+bx+c
use the three given points to find the three unknown constants a, b, and c:
-2=a+b+c............1
-2=4a+2b+c......... 2
-4=9a+3b+c...........3
equation 2 minus equation 1: 3a+b=0..........4
equation 3 minus equation 2: 5a+b=-2.........5
equation 5 minus equation 4: 2a=-2, so a=-1
plug a=-1 in equation 4: -3+b=0, so b=3
Plug a=-1, b=3 in equation 1: -2=-1+3+c, so c=-4
the parabola is y=-x²+3x-4

double check: when x=1, y=-1+3-4=-2
when x=2, y=-4+6-4=-2
when x=3, y=-9+9-4=-4
Yes.


8 0
2 years ago
A crossover trial is a type of experiment used to compare two drugs. Subjects take one drug for a period of time and then switch
zysi [14]

Answer:

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369

df=n-1=7-1=6

p_v =2*P(t_{(6)}

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

Step-by-step explanation:

We have the following info given by the problem

Subject  1 2 3 4 5 6 7

Drug A  6 3 4 5 7 1 4

Drug B  5 1 5 5 5 2 2

x=value for drug A , y = value for drug B

x: 6 3 4 5 7 1 4  

y: 5 1 5 5 5 2 2

We want to verify if the mean response differs between the two drugs then  the system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x = 0

Alternative hypothesis: \mu_y -\mu_x \neq 0

We can begin calculating the difference d_i=y_i-x_i and we obtain this:

d: -1, -2, 1, 0, -2, 1, -2

Now we can calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=-0.714

Now we can find the the standard deviation for the differences, and we got:

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}}=1.38

And now we can calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-0.714 -0}{\frac{1.38}{\sqrt{7}}}=-1.369

Now we can find the degrees of freedom given by:

df=n-1=7-1=6

We can calculate the p value, since we have a two tailed test the p value is given by:

p_v =2*P(t_{(6)}

We see that the p value is higher than the ususal significance levels commonly used of 1% or 5% so then we can conclude that we FAIL to reject the null hypothesis, and there is not enough evidence to conclude that we have a different response between the two drugs

7 0
3 years ago
The price of a notebook was
Pie

Old price: p1 = $ 3.90;

New price: p2 = $ 3.40.


The percentual decrease is given by

d(%) = [ (p2 - p1) / p1 ] * 100 %

d(%) = [ (3.40 - 3.90) / 3.90 ] * 100 %

d(%) = [ - 0.50 / 3.90 ] * 100 %

d(%) = - 0.128 * 100 %

d(%) = - 12.8 % (approximately)


So the price fell 12.8 % approximately.


I hope this helps. =)

4 0
3 years ago
Which shows the list above in order from LEAST to GREATEST<br><br> I’ll mark brainlist : )
irina1246 [14]
The answer is A!

-4.82, -4(2/3) = - 4.667, sqrt 15 is 3.873, 4.15, 465% is 4.65, and 1.5pi =4.65
Hope this helps!
7 0
2 years ago
Based on the function h(t), what will be the account value five years after the account is opened?
bija089 [108]

Answer:

Option B

Step-by-step explanation:

f(t) = 5000

g(t) = 250t

h(t) = f(t) + g(t) = 5000 + 250t

After 5 years, the amount of money in the account is:

h(t = 5) = 5000 + 250(5) = 5000 + 1250 = 6250$

5 0
3 years ago
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