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mel-nik [20]
3 years ago
5

Thirty-five percent of what number is 17.5?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
4 0
I believe its 50 because 0.35x50=17.5     (35%=0.35)
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Factor the polynomial: 2x(x - 4) + 7 (x - 4)
steposvetlana [31]

Answer:

Step-by-step explanation:

With this question, we just have to group the terms, so in this case, we can remove the common term (x - 4), and then group the rest of them

If we do that we get:

(x - 4) (2x + 7)

Hope this helps,

Cate

6 0
3 years ago
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4/5÷1/10<br><br><br><br><br>in mixed number from please help idk!!!​
Alex_Xolod [135]
The answer is 8 To you question
7 0
3 years ago
The circumstance of a circle is 16 ft<br><br> The radius is_____ ft
kari74 [83]

Answer:

8ft

Step-by-step explanation:

Circumference of a circle equation; πd or2πr

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16 = 2r then you can divide both sides by 2

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5 0
3 years ago
What steps do i take to prove this? i have a few more
Maksim231197 [3]

Answer:

They are opposite angles. If you rotate the figure SQM 180 degrees counter clockwise, they will be the exact same triangle and therefore the exact same measure.

Step-by-step explanation:

5 0
2 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
laiz [17]

<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


6 0
3 years ago
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