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nika2105 [10]
3 years ago
6

How many 1/4 pound servings of walnuts, s, are in 3/4 pound ofwalnuts?​

Mathematics
2 answers:
andrew-mc [135]3 years ago
4 0

Answer:

3 servings

Step-by-step explanation:

Take the number of pounds and divide by the size of the servings

3/4 ÷ 1/4

Copy dot flip

3/4 * 4/1

3/1 * 4/4

3 servings

Lady_Fox [76]3 years ago
3 0

Answer:

3

Step-by-step explanation:

To find this out, you need to use division. Divide 3/4 by 1/4.

3/4 divided by 1/4 equals 3.

So there are 3 1/4 pound servings in 3/4 pounds of walnuts.

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A dealer bought an item for $20 sold it for 24 bought it for 25
yuradex [85]

Answer:

$3

Step-by-step explanation:

Started with $20 Sold for $24 Bought it for $25 Then sold it for $28

so, $24 -$20= so she made $4.

then she bought it for $25-$24= so she only made $1

Finally she sold it for $28-$25 so she made a total of $3

6 0
2 years ago
Find the x-intercepts for the parabola defined by the equation below. y = x2 - 9x + 18
Alla [95]

Answer:

x-intercept:  (6,0), (3,0)

Step-by-step explanation:

I graphed the equation and cannot upload the picture of it

3 0
3 years ago
Read 2 more answers
Calculate two iterations of Newton's Method to approximate a zero of the function using the given initial guess. (Round your ans
VikaD [51]

Answer:

The two iterations of f(x) = 1.5598

Step-by-step explanation:

If we apply  Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.

xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)

Given;

f(xₙ) = cos x, then  f'(xₙ) = - sin x

cos x / - sin x = -cot x

substitute in "-cot x" into the equation

xₙ₊₁ = xₙ - (- cot x)

xₙ₊₁ = xₙ + cot x

x₁ = 0.7

first iteration

x₂ = 0.7 + cot (0.7)

x₂ =  0.7 + 1.18724

x₂ = 1.88724

 

second iteration

x₃ = 1.88724 + cot (1.88724)

x₃ = 1.88724 - 0.32744

x₃ = 1.5598

To four decimal places = 1.5598

4 0
3 years ago
I'm lazzzzzzzzy pls answer asap
elena-s [515]
The second one because you times the exponents together
8 0
3 years ago
Read 2 more answers
The average height of students at UH from an SRS of 12 students gave a standard deviation of 2.5 feet. Construct a 95% confidenc
Vanyuwa [196]

Answer:

c. [1.771;4.245] feet

Step-by-step explanation:

Hello!

The variable of interest is

X: height of a student at UH

X~N(μ;σ²)

You have to estimate the population standard deviation using a 95% confidence interval.

The statistic to use for the interval is a student Chi-Square with n-1 degrees of freedom. First you have to calculate the CI for the population variance:

[\frac{(n-1)S^2}{X^2_{n-1;1-\alpha /2}} ;\frac{(n-1)S^2}{X^2_{n-1;\alpha /2}} ]

X^2_{n-1;1-\alpha /2}= X^2_{11;0.975}= 21.920

X^2_{n-1;\alpha /2}= X^2_{11;0.025}= 3.816

n=12

S= 2.5

[\frac{11*6.25}{21.920} ;\frac{11*6.25}{3.816}} ]

[3.136; 18.016] feet²

Then you calculate the square root of both limits to get the CI for the population standard deviation:

[√3.136; √18.016]

[1.771;4.245] feet

I hope this helps!

4 0
3 years ago
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