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kiruha [24]
3 years ago
15

Please solve! It's due next period!

Mathematics
1 answer:
astra-53 [7]3 years ago
6 0
1.
-3x-4>8
-3x>12
x<-4

2.
-y+4y+3(y-5)
3y+3y-15
6y-15

3.
3*45=135
135*1.08625=146.64375
round
$146.64

4. multily exponents
(-4x^6y)^3=(-4)^3(x^6)^3(y)^3=-64x^18y^3


5. 4+2+4=10
2/10time1/9=1/45
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A certain virus infects one in every 300 people. A test used to detect the virus in a person is positive 90​% of the time when t
garik1379 [7]

Answer:

a)  P[A/B] = 0,019     or     P[A/B] = 1,9 %

b)  P[A- /B-] = 0,9996       or    P[A- /B-] = 99,96 %

Step-by-step explanation:

Bayes Theorem :

P[A/B]  =  P(A) * P[B/A] / P(B)

The branches of events are as follows

Condition 1        real infection     1/300        and     not infection  299/300

Then

1.-    1/300      299/300

When the test is done   (virus present)  0,9 (+)    0,15 (-)

2.-   299/300

When the test is done  ( no virus )   0,15  (+)     0,85 (-)

Then:

P(A) = event person infected          P(B)  =  person test positive

a) P[A/B]  = P(A) * P[B/A] / P(B)

where   P(A)  = 1/300  =   0,0033   P[B/A] = 0,9    

Then P(A) * P[B/A] =  0,0033*0,9  =  0,00297

P(B)   is    ( 1/300 )*0,9  +  (299/300)*0,15

P(B) = 0,0033*0,9 + 0,9966*0,15    ⇒  P(B) = 0,1524

Finally

P[A/B] =  0,00297 /0,1524

P[A/B] = 0,019     or     P[A/B] = 1,9 %

b) Following sames steps:

P[A- /B-] = (299/300) * 0,85  / (299/300) * 0,85 + (1/300 * 0,1)

P[A- /B-] = 0,8471 /0,8474

P[A- /B-] = 0,9996       or    P[A- /B-] = 99,96 %

6 0
3 years ago
-| -8 | |-(-8) are they equal ? Or which one is more ?
satela [25.4K]

Answer:

-| -8 |  is less than |-(-8)|

Step-by-step explanation:

-| -8 | =-8

|-(-8)| =8

they are not equal

-| -8 |  is less than |-(-8)|

5 0
3 years ago
China has a population of approximately 1,322,000,000 people. Express this number in scientific notation. A) 1.322 x 109 B) 1.32
Alona [7]
That would be 1.322 x 10^9

Its A
4 0
3 years ago
Read 2 more answers
NEED HELP !!!!!! READDD THE QUESTION THERE ARE TWO PARTS
mel-nik [20]

We have to find horizontal component of Mayosons velocity.

#a

\\ \tt\bull\leadsto V_x=vsin\theta

\\ \tt\bull\leadsto V_x=2.5sin36

\\ \tt\bull\leadsto V_x=2.5(0.58)

\\ \tt\bull\leadsto V_x=1.45m/s

#b

Here 2 vectors A=8 and B=2.5

\\ \tt\bull\leadsto \overrightarrow{R}

\\ \tt\bull\leadsto \sqrt{A^2+B^2+2ABcos\Theta}

\\ \tt\bull\leadsto \sqrt{8^2+2.5^2+2(8)(2.5)cos36}

\\ \tt\bull\leadsto \sqrt{64+6.25+40(0.8)}

\\ \tt\bull\leadsto \sqrt{70.25+32}

\\ \tt\bull\leadsto \sqrt{102.25}

\\ \tt\bull\leadsto 10.15m/s

3 0
3 years ago
An exam consists of 50 multiple choice questions. Based on how much you studied, for any given question, you think you have a pr
astraxan [27]

Answer: (a) mean = 32.00

(b)Standard error = 0.068

It is expected that the shape will approximately large because n is large.

(c)P(z< 0.60)= 0

Step-by-step explanation:

a. Mean = nP= 0.64× 50 = 32.00(2dp)

P= 0.64

b. Standard error = √ p(1-p)/n

= √0.64(0.36)/50

= 0.068(3dp)

c. Using P(Z<X - U/S)

Where S = standard error

U = mean = 0.64

(c)P(z< 0.60)=

= P( z< 0.60 - 0.64/0.068)

= P( z < -5.88)

= 0.

3 0
3 years ago
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