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Oksanka [162]
3 years ago
15

PLEASE HELP BRAINLIEST TO WHOEVER ANSWERS RIGHT

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
6 0
To calculate the IQR, we need the radian, which is the middle number of each column, namely (86,82) for each exam.
Above the middle number, we have 5 values.  The middle value (of the upper part) is Q3, which is on the third line, or (92,85).
Below the middle number, we also have 5 values.  The middle (of the lower half) is Q1, which is on the 9th line (80,78)

The IQR is the difference between Q3 and Q1, namely
(92-80, 85-78) = (12, 7)
Since 12>7, we conclude that the IQR of the mid-term is higher than the final.
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4 0
3 years ago
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On
quester [9]

Answer:

\large\boxed{C.\ 2x^3-x^2-18x+9}

Step-by-step explanation:

\text{Use}\ a^2-b^2=(a-b)(a+b)\qquad(*)\\\\\underbrace{(x-3)(x+3)}_{(*)}(2x-1)=(x^2-3^2)(2x-1)=(x^2-9)(2x-1)\\\\\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\=(x^2)(2x)+(x^2)(-1)+(-9)(2x)+(-9)(-1)\\\\=2x^3-x^2-18x+9

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3 years ago
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