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3 years ago

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Certain items are purchased jointly. If each person pays 8 coins, the surplus is 3 coins, and if each person gives 7 coins, the

deficiency is 4 coins. Let x represent the number of people and y the number of coins needed to purchase the items. Find the number of people and the number of coins used to purchase the items.

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

7 people purchase the items and they used 53 coins

Step-by-step explanation:

Let x represent the number of people.

Let y be the number of coins needed to purchase the items.

If each person pays 8 coins, the surplus is 3 coins. This is illustrated below:

8x = y + 3 (1)

if each person gives 7 coins, the deficiency is 4 coins. This is illustrated below:

7x = y — 4 (2)

Solving by elimination method: subtract equation(2) from equation (1). This is illustrated below:

8x = y + 3 (1)

— (7x = y — 4) (2)

x = 7.

Next, Substituting the value of x into any of the equation to obtain y. In this case I will be using equation 1 as illustrated below:

8x = y + 3 (1)

8(7) = y + 3

56 = y + 3

Collect like terms

y = 56 — 3

y = 53

Therefore, 7 people purchase the items and they used 53 coins

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Answer:

Part 1) $u< 5.5$

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Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

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$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

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$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

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Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

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The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

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Divide by -0.15 both sides

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Rewrite

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In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

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