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Romashka-Z-Leto [24]
3 years ago
9

A family of four spent $104 for tickets to a concert on Friday and they spent $140 for tickets to dinner theater on Saturday.Wha

t was the cost per person to attend these events
Mathematics
2 answers:
BigorU [14]3 years ago
5 0

Answer:

$61

Step-by-step explanation:

To determine the cost per person to attend these events, you have to add the cost of the tickets for the concert plus the cost of the tickets for dinner theater. After finding the total amount that was spent, you have to divide this by 4 that is the number of people:

Total cost= $104+$140

Total cost= $244

Cost per person= $244/4

Cost per person= $61

According to this, the cost per person to attend these events is $61.

AfilCa [17]3 years ago
3 0

Answer:

Cost of first event: $26 per person

Cost of second event: $35 per person

Cost of both events together: $61 per person

Step-by-step explanation:

In the first event, the four people spent $104, so the cost per person of this event is:

104 / 4 = $26

Each person pays $26 for this event.

For the second event, the four people spent $140, so the cost per person of this event is:

140 / 4 = $35

The cost per person to attend both events together is:

26 + 35 = $61

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3 years ago
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Solve the following inequality: x+5≤(−x+2)+x
vesna_86 [32]

Answer:

<h2>x ≤ - 3</h2>

Step-by-step explanation:

x + 5 ≤ ( - x + 2) + x

<u>Remove the parenthesis</u>

That's

x + 5 ≤ - x + 2 + x

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4 0
3 years ago
A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three diff
igor_vitrenko [27]

Answer:

(a) 31101

(b) $5.65

(c) $113.38

Step-by-step explanation:

The complete question is:

A regional automobile dealership sent out fliers to prospective customers indicating that they had already won one of three different prizes: an automobile valued at $20,000, a $125 gas card, or a $5 shopping card. To claim his or her prize, a prospective print on the back of the flier listed the probabilities of winning. The chance of winning the car was 1 out of 31,101, the chance of winning the gas card was 1 out of 31,101, and the chance of winning the shopping card was 31, 099 out of 31,101.

Solution:

The information provided is as follows:

P(\text{Car})=\frac{1}{31101}\\\\P(\text{Gas Card})=\frac{1}{31101}\\\\P(\text{Shopping Card})=\frac{31099}{31101}

(a)

The number of fliers the automobile dealership sent​ out is, <em>n</em> = 31,101.

This is because the probability of winning any of the three prize is out of 31,101.

(b)

Compute the expected value of the prize won by a prospective customer receiving a​ flier as follows:

E(X)=\sum x\times P(X=x)

         =[20000\times \frac{1}{31101}]+[125\times \frac{1}{31101}]+[5\times \frac{31099}{31101}]\\\\=0.6431+0.0040+4.9997\\\\=5.6468\\\\\approx 5.65

Thus, the expected value of the prize won by a prospective customer receiving a​ flier is $5.65.

(c)

Compute the standard deviation of the prize won by a prospective customer receiving a​ flier as follows:

SD(X)=\sqrt{V(X)}=\sqrt{E(X^{2}-(E(X))^{2}}

           =\sqrt{[(20000)^{2}\times \frac{1}{31101}+(125)^{2}\times \frac{1}{31101}+(5)^{2}\times \frac{31099}{31101}]-(5.65)^{2}}\\\\=\sqrt{12854.9011}\\\\=113.37947\\\\\approx 113.38

Thus, the standard deviation of the prize won by a prospective customer receiving a​ flier is $113.38.

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3 years ago
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1 year ago
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