Answer:
<h2>
8 units²</h2>
Step-by-step explanation:
Let side of the square = a
The , Area of square = a²
Now, Midpoint of Diagonal DB is E
And DE = 2 units
So, DB = 2 DE = 2 × 2 = 4 units
Now, using Pythagoras theorem in ∆ BCD
DB² = DC² + BC²
plug the values

Collect like terms

Evaluate the power

Swipe the side of the equation

Divide both sides of the equation by 2

Calculate

Therefore, The area of the square is 8 sq.units.
Hope this helps..
Best regards!!
Question:
Solution:
Let the following equation:
![\sqrt[]{12-x}=\text{ x}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B12-x%7D%3D%5Ctext%7B%20x%7D)
this is equivalent to:
![(\sqrt[]{12-x})^2=x^2](https://tex.z-dn.net/?f=%28%5Csqrt%5B%5D%7B12-x%7D%29%5E2%3Dx%5E2)
this is equivalent to:

this is equivalent to:

thus, we can conclude that
x= 3.
We have that
(14x2 - 3x3 + 9x4) - (-14 + 13x3 + 11x4)=<span>14x2 - 3x3 + 9x4 +14 - 13x3 - 11x4
</span>(14x2 - 16x3 +14 - 2x4)
then
-2x4-16x3+14x2+14=0--------------> this is the <span>standard form
simplify </span><span>dividing the entire expression by two
</span><span>-x4-8x3+7x2+7=0
the answer is
</span>-x4-8x3+7x2+7=0<span>
</span>
its B because all the other ones don't make sense for the graph and you just do the slope and it is -3