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Answer:
we reject H₀
Step-by-step explanation: Se annex
The test is one tail-test (greater than)
Using α = 0,05 (critical value ) from z- table we get
z(c) = 1,64
And Test hypothesis is:
H₀ Null hypothesis μ = μ₀
Hₐ Alternate hypothesis μ > μ₀
Which we need to compare with z(s) = 2,19 (from problem statement)
The annex shows z(c), z(s), rejection and acceptance regions, and as we can see z(s) > z(c) and it is in the rejection region
So base on our drawing we will reject H₀
The missing aspect of this question is shown in the attached image, which is that the letters correspond to vertices of a parallelogram.
A key feature of the parallelogram is that the diagonals bisect each other, therefore:
PT = TR
QT = TS
With this information we can now plug in the equations and solve for the variables x and y.
PT = TR
2x = y+4
y = 2x - 4
QT = TS
x + 2 = y
We now have two equations for the variable y. With this we can solve for x.
2x - 4 = x + 2
x = 6
y = x + 2
y = 6 + 2
y = 8
Once we solved for the variable x, we simply placed that value back into one of the previous equations and solved for y. The results are x = 6, y = 8.
A key feature of the parallelogram is that the diagonals bisect each other, therefore:
PT = TR
QT = TS
With this information we can now plug in the equations and solve for the variables x and y.
PT = TR
2x = y+4
y = 2x - 4
QT = TS
x + 2 = y
We now have two equations for the variable y. With this we can solve for x.
2x - 4 = x + 2
x = 6
y = x + 2
y = 6 + 2
y = 8
Once we solved for the variable x, we simply placed that value back into one of the previous equations and solved for y. The results are x = 6, y = 8.