Answer:
Jogging = 10 hours
Swimming = 7 hours
Cycling = 3 hours
Step-by-step explanation:
J = Hours jogging
S = Hours swimming
C = Hours cycling
Since jogging is the activity that burns the most calories, we should maximize the number of hours jogging:
![C+S+J = 20\\C+S=20-J\\J\leq C+S\\J\leq 20-J\\J\leq 10](https://tex.z-dn.net/?f=C%2BS%2BJ%20%3D%2020%5C%5CC%2BS%3D20-J%5C%5CJ%5Cleq%20C%2BS%5C%5CJ%5Cleq%2020-J%5C%5CJ%5Cleq%2010)
Therefore, the man should jog for 10 hours.
Since swimming is the activity that burns the second most calories, we should maximize swimming hours:
![C+S=10\\S\leq 7\\S=7\\C=3](https://tex.z-dn.net/?f=C%2BS%3D10%5C%5CS%5Cleq%207%5C%5CS%3D7%5C%5CC%3D3)
In order to maximize the number of calories burn, the man should go jogging for 10 hours, swimming for 7 hours and cycling for 3 hours.
Answer:
Isolate the variables in all cases. Note the equal sign, what you do to one side, you do to the other.
a) 3x = 18
Isolate the variable, x. Divide 3 from both sides:
(3x)/3 = (18)/3
x = 18/3
x = 6
b) 2x = 9
Isolate the variable, x. Divide 2 from both sides:
(2x)/2 = (9)/2
x = 9/2
x = 4.5
c) (x/5) = 7
Isolate the variable, x. Multiply 5 to both sides:
(x/5)(5) = (7)(5)
x = 7 * 5
x = 35
d) x/2 = 6.5
Isolate the variable, x. Multiply 2 to both sides:
(x/2)(2) = (6.5)(2)
x = 6.5 * 2
x = 13
~
80 is the median, heres an easy way to look at it
74, 77,78,78,79,79,80,80,80,80,80,81,81,82,82,82,82,82
write that down and cross out one at a time on each end until you get to the last one, or two in the middle. If it comes down to 2 numbers add and divide by 2.
Answer:
y = 2x-3
Step-by-step explanation:
y – 1 = 2(x – 2)
Distribute
y-1 =2x-4
Add 1 to each side
y-1+1 = 2x-4+1
y = 2x-3
Answer:
Probability (P) (k successes out of n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n! / (k! * (n-k)!)
for this problem n=20, p = 1/6(probability of rolling 1 two) is approximately 0.1667
P ( of getting more that 3 two's) = 1 -P(0 two's out of 20 trials) -P(1 two out of 20 trials) -P(2 two's out of 20 trials) -P(3 two's out of 20 trials)
P ( of getting more that 3 two's) = 1 -0.026 -0.104 -0.198 -0.238 = 0.434
My answer is A