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Darya [45]
3 years ago
12

There are 150 marbles in 3 bags of marbles. Which of the following expresses the ratio of marbles to bags?

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0
The expression of the ratio is 150:3
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The hexagon GIKMPR is regular. The dashed line segments form 30 degree angles.
Gwar [14]

Answer:

The correct option is (D).

Step-by-step explanation:

It is given that GIKMPR is regular hexagon. It means it has 6 vertices.

Since the central angle is 360 degree. Therefore the central angle between two consecutive vertices is

\frac{360^{\circ} }{6}=60^{\circ}

It is given that the dashed line segments form 30 degree angles.

We have rotated the hexagon about O to map PQ to RF. Since P and R are consecutive vertices, therefore the angle between them is 60 degree.

The vertex R is immediate next to the vertex P in clockwise direction.

So if we rotate the hexagon at 60 degree clockwise about O, then we can maps PQ to RF.

360^{\circ}-60^{\circ}=300^{\circ}

Therefore we can also rotate the hexagon at 300 degree counterclockwise about O, then we can maps PQ to RF.

Therefore option D is correct.


8 0
3 years ago
Can someone please explain how to do this.
lutik1710 [3]
Set the to equal:

x^2 - 4x+4 = 2x-4
 solve for X

subtract 2x from each side:
x^2 -6x + 4 = -4

subtract 4 from each side:

x^2 -6x = -8

add 8 to both sides:

x^2 -6x +8 = 0

factor the polynomial:

x = 4 and x = 2

using the line equation replace x with 2 and 4 and solve for y

y = 2(2) - 4 = 0
y = 2(4)-4 = 4

so the 2 points the line  crosses the curve is (2,0) and (4,4)

using those 2 points you can calculate the length:
 distance = sqrt((x2-x1)^2 +(y2-y1)^2

distance = sqrt( (4-2)^2 + (4-0)^2)

distance = sqrt (2^2 + 4^2)
 distance = sqrt (4+16)
= sqrt 20 
= 2 sqrt(5)  EXACT LENGTH


4 0
3 years ago
Solve the quadratic equation by completing the square.<br> QUESTION ATTCHED BELOW!!!!!!!!!!
Mariulka [41]

Answer:

x ≈ - 9.41, x ≈ - 6.59

Step-by-step explanation:

Given

x² + 16x + 62 = 0 ( subtract 62 from both sides )

x² + 16x = - 62

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(8)x + 64 = - 62 + 64

(x + 8)² = 2 ( take the square root of both sides )

x + 8 = ± \sqrt{2} ( subtract 8 from both sides )

x = - 8 ± \sqrt{2}

Hence

x = - 8 - \sqrt{2} ≈ - 9.41

x = - 8 + \sqrt{2} ≈ - 6.59

4 0
3 years ago
Read 2 more answers
What is <br><br> 0.3(−32.48−14.02)​
shtirl [24]

Answer:

-13.95

Step-by-step explanation:

0.3(-32.48-14.02)

0.3(-46.5)

=-13.95

hope this helps!

8 0
3 years ago
X/2 = Y/3 = Z/4. prove that :2X-Y+5Z / 3Y-X =3. note :: (/) is for a fraction aka divide. help pls I've been stuck on it for a f
sweet-ann [11.9K]

The given equation

x/2 = y/3 = z/4

can be broken into three separate equations which I'll call equations (A), (B) and (C)

  • x/2 = y/3 ..... equation (A)
  • y/3 = z/4 .... equation (B)
  • x/2 = z/4 .... equation (C)

We'll start off solving for z in equation (C)

x/2 = z/4

4x = 2z ... cross multiply

2z = 4x

z = 4x/2 ... divide both sides by 2

z = 2x

Now let's solve for y in equation (A)

x/2 = y/3

3x = 2y

2y = 3x

y = 3x/2

y = (3/2)x

y = 1.5x

The results of z = 2x and y = 1.5x both have the right hand sides in terms of x. This will allow us to replace the variables y and z with something in terms of x, which means we'll have some overall expression with x only. The idea is that expression should simplify to 3 if we played our cards right.

We won't be using equation (B) at all.

---------------------

The key takeaway from the last section is that

  • z = 2x
  • y = 1.5x

Let's plug those items into the expression (2x-y+5z)/(3y-x) to get the following:

(2x-y+5z)/(3y-x)

(2x-y+5(2x))/(3y-x) ..... plug in z = 2x

(2x-y+10x)/(3y-x)

(12x-y)/(3y-x)

(12x-1.5x)/(3(1.5x)-x) .... plug in y = 1.5x

(12x-1.5x)/(4.5x-x)

(10.5x)/(3.5x)

(10.5)/(3.5)

3

We've shown that plugging z = 2x and y = 1.5x into the expression above simplifies to 3. Therefore, the equation (2x-y+5z)/(3y-x) = 3 is true when x/2 = y/3 = z/4. This concludes the proof.

5 0
3 years ago
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