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ad-work [718]
3 years ago
10

5/6x+7=12-5/12x solve this equation

Mathematics
2 answers:
adelina 88 [10]3 years ago
6 0
5/6x + 7 = 12 - 5/12x

subtract 7 from each side

5/6x = 5 - 5/12x

add 5/12x to each side

5/12x + 5/6x = 5

Find common denominator

5/12x + 10/12x = 5

combine like terms

15/12x = 5

divide each side by 15/12 (multiply the reciprocal)

x = 5 × 12/15
x = 60/15
x = 4
natima [27]3 years ago
3 0

Simplify both sides of the equation

5/6 x +7= 12 -5/12 x

5/6 x +7= 12+ -5/12 x

5/6 x +7 = -5/12 x +12

Add 5/12x to both sides

5/6 x +7 + 5/12 x= -5/12 x +12+5/12 x

5/4 x +7 = 12

Subtract 7 from both sides

5/4 x +7-7 = 12-7

5/4 x = 5

Multiply both sides by 4/5

(4/5)*(5/4 x) = (4/5)*5

x= 4


I hope that's help !

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Melinda paints 7/8 of a wall in 1 1/6 hours. What part of a wall does Melinda paint in 1 minute?
melisa1 [442]
This is the way we are going to solve it.

1h = 60m ----------Steps

1. 7/8w=(1+1/6)h 

2. 7/8w=(6/6+1/6)h

3. 7/8w=7/6*60m

4. 7/8w=(7*6*10*m)/6

5. 7/8w=70m

6. m=(7/8w)/70

<span>7. m=1/80w
</span>
Answer: Melinda paints 1/80 of the wall in 1 minute.

Happy studying ^-^
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4 years ago
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trapecia [35]

Answer:

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Step-by-step explanation:

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3 years ago
Find the product of the complex numbers
lukranit [14]

Answer:

17.32 + 10i

Step-by-step explanation:

The product of the complex numbers;

z, = 5( cos 20° + i sin 20°)

za = 4( cos 10° + i sin 10°)

5( cos 20° + i sin 20°) × 4( cos 10° + i sin 10°)

= 20(cos20(cos10) + i sin20(cos10) + i sin10(cos20) + isin20(i sin10))

= 20(cos20(cos10) + i sin20(cos10) + i sin10(cos20) + sin20(sin10)i^2 )

And i^2 = -1

= 20(cos20(cos10) + i sin20(cos10) + i sin10(cos20) - sin20(sin10) )

= 20(cos20(cos10) - sin20(sin10) + i(sin20(cos10) + sin10(cos20)))

= 20(0.866 + i(0.5))

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8 0
4 years ago
Why does the sum of -4 and 3 complain more than the sum of -3 and 5
dem82 [27]
The sum of -4 and 3 complain more because its negative

5 0
4 years ago
Please explain how you get the answer. show work.
ladessa [460]
I think it's b okay Im sure
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