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tankabanditka [31]
4 years ago
11

Why does the sum of -4 and 3 complain more than the sum of -3 and 5

Mathematics
1 answer:
dem82 [27]4 years ago
5 0
The sum of -4 and 3 complain more because its negative

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Write 7x10x10x10x10 with an exponent
polet [3.4K]

Answer:

7x10^4

Step-by-step explanation:

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6 0
3 years ago
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Find the explicit formula for the general nth term of the arithmetic sequence described below. Simplify the formula and reduce a
NemiM [27]

Answer:

an = 4/3n - 13/3.

Step-by-step explanation:

The first term is a1,

a24 = a1 + 23d

83/3 = a1 + 4/3* 23

a1 =    83/3 - 92/3

a1 = -9/3 = -3.

So the nth term an =  -3 + 4/3(n - 1)

an = -3 + 4/3 n - 4/3

an = 4/3n - 13/3

6 0
3 years ago
if the value of c is negative, you would need zero pairs to model the factorization of the polynomial. the x-tiles on the board
Yuliya22 [10]

Answer:

value of c is negative

constant are in factor bla bla.

Step-by-step explanation:

6 0
2 years ago
In the figure above, the measure of <BDE is 20 and CD is perpendicular to DE. What is the measure of <ADC ?​
notsponge [240]

Answer:

∠ ADC = 110°

Step-by-step explanation:

∠ CDE = 90° ( angle between perpendicular lines ) , then

∠ CDB + ∠ BDE = 90°

∠ CDB + 20° = 90° ( subtract 20° from both sides )

∠ CDB = 70°

∠ ADC and ∠ CDB are adjacent angles on a straight line and sum to 180° , so

∠ ADC + ∠ CDB = 180° , that is

∠ ADC + 70° = 180° ( subtract 70° from both sides )

∠ ADC = 110°

6 0
2 years ago
Find UV (Pic Stated Below)
natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i)  {Right angles}

∠QBA = ∠VBA ...(ii)  {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle


∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)


using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV  (using (i) and (ii))

∠BAQ=∠BAV...(v)


Now consider triangles AQB and AVB;

∠BAQ=∠BAV  {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB  {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

<u>Hence UV=29 is final answer.</u>

7 0
3 years ago
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