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3 years ago

When x = 8, y = 18. find y when x = 84?

Mathematics

1 answer:

vredina [299]3 years ago

5 0

8÷18=84÷y
8y=18×84
8y=1512
y=189

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7m + 3mn<br> when m = 3 and n = -4

nadya68 [22]

Answer:

-15

Step-by-step explanation:

When m=3 and n=-4

So, put the values

7(3)+3(3)(-4)

-> -15

4 0

3 years ago

Read 2 more answers

If 4x-3<32, Which of the following are solutions: 26/3, 9.1, 20, or -6?

ValentinkaMS [17]

The answer is :
$4x - 3 < 32 \\ 4 x < 32 + 3 \\ 4 x < 35 \\ x < \frac{35}{4} \\$
$x < 8.75$
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3 years ago

Drag each title to the correct box. Not all tiles will be used

mestny [16]

Answer:

4, 1, 6.

See explanation

Step-by-step explanation:

You are given the equation

$d=vt-\dfrac{1}{2}at^2$

First subtract $vt$ from both sides:

$d-vt--\dfrac{1}{2}at^2$

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$vt-d=\dfrac{1}{2}at^2\ \ \ \ (1)$

Now multiply (1) by 2:

$2(vt-d)=at^2\ \ \ \ \ (2)$

At last, divide by $a$

$t^2=\dfrac{2(vt-d)}{a}\ \ \ \ \ (3)$

5 0

3 years ago

F(x) has domain (-4,-2, 0, 2, 4) and range

CaHeK987 [17]

Answer:

1/2

Step-by-step explanation:

I just did the problem on edgenuity.

8 0

2 years ago

Merle Fonda opened a new savings account. She deposited $40,000 at 10% compounded semiannually. At the start of the fourth year,

IrinaVladis [17]

Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.

For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253

For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913

Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)

8 0

2 years ago