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3 years ago

Find the volume of the figure

Mathematics

1 answer:

nevsk [136]3 years ago

5 0

Answer:

First of all are you given formulas, if yes then apply them to what you are given and find the missing outputs. I'm writing a test tomorrow on Euclidean Geometry

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A rotation is shown in the drawing:

madam [21]

Answer:

counterclockwise 90-degree rotation

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

If <3 measures 123°, what is the measure of <7?

BaLLatris [955]

Answer:

assuming <3 is supplementary to <7 then <7 is 57

Step-by-step explanation:

180-123=57

3 0

3 years ago

On a vacation in Puerto Rico, Rose jumped off a cliff into a river in EL Yunque Forest Reserve. Her height as a function of time

balandron [24]

H (t) = - 16t ^ 2 + 16t + 480
For this case, the first thing to do is to match the polynomial to zero to find the roots.
We have then:
0 = -16t ^ 2 + 16t + 480
From here, we obtain the following roots of the polynomial:
t1 = -5
t2 = 6
We ignore the negative root because the time is always greater than zero.
Answer:
it takes Rose to hit the water about
t = 6 seconds

4 0

3 years ago

Read 2 more answers

Please show work on these questions!!!

asambeis [7]

Answer:

- 14π/9; 108°; -√2/2; √2/2

Step-by-step explanation:

To convert from degrees to radians, use the unit multiplier $\frac{\pi }{180}$

In equation form that will look like this:

- 280° × $\frac{\pi }{180}$

Cross canceling out the degrees gives you only radians left, and simplifying the fraction to its simplest form we have $-\frac{14\pi }{9}$

The second question uses the same unit multiplier, but this time the degrees are in the numerator since we want to cancel out the radians. That equation looks like this:

$\frac{3\pi }{5}$ × $\frac{180}{\pi }$

Simplifying all of that and canceling out the radians gives you 108°.

The third one requires the reference angle of $\frac{3\pi }{4}$ .

If you use the same method as above, we find that that angle in degrees is 135°. That angle is in QII and has a reference angle of 45 degrees. The Pythagorean triple for a 45-45-90 is (1, 1, √2). But the first "1" there is negative because x is negative in QII. So the cosine of this angle, side adjacent over hypotenuse, is $-\frac{1}{\sqrt{2} }$

which rationalizes to $-\frac{\sqrt{2} }{2}$

The sin of that angle is the side opposite the reference angle, 1, over the hypotenuse of the square root of 2 is, rationalized, $\frac{\sqrt{2} }{2}$

And you're done!!!

7 0

4 years ago

In how many ways can five indistinguishable rooks be placed on an 8-by-8 chess- board so that no rook can attack another and nei

german

The are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty

<h3 /><h3>What involves the rook polynomial? </h3>

The rook polynomial as a generalization of the rooks problem

Indeed, its result is that 8 non-attacking rooks can be arranged on an 8 × 8 chessboard in r8.

Hence, 8! = 40320 ways.

Therefore, there are 40320 ways in which the 5 indistinguishable rooks be can be placed on an 8-by-8 chess- board so that no rook can attack another and neither the first row nor the first column is empty.