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3 years ago

What is the factorization of the expression below 16x2 - 49?

Mathematics

2 answers:

mrs_skeptik [129]3 years ago

7 0

$16 {x}^{2} - 49 \\ = {(4x)}^{2} - {7}^{2} \\ = (4x - 7)(4x + 7)$

Vilka [71]3 years ago

4 0

Answer:

16 {x}^{2} - 49 \\ = {(4x)}^{2} - {7}^{2} \\ = (4x - 7)(4x + 7)

Step-by-step explanation:

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1.How do you turn 34% into a fraction.

bearhunter [10]

For the first two, put it them over 100. So number 1 would be 34/100 or 17/50 reduced. Number 2 is 77.5/100 and since it is a decimal, I would keep it at over 100. Number 3 put 8/10 or 4/5 reduced and number 4 is different. Think of it as money and how a quarter is in relation to a dollar. You have 4 quarters in a dollar, so since you have .25%, it is 1/4.

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3 years ago

For the given image and scale factor, which ordered pair is one of the pre-image vertices if the center of the pre-image is also

Virty [35]

Answer:

Step-by-step explanation:its the first one 3 5ths ,1

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3 years ago

Read 2 more answers

Quick it is due in 30 mins plz do quick

dimulka [17.4K]

Answer:

1. 69°

2. 97°

3. 145°

4. 150°

5. 128°

6. 74°

Step-by-step explanation:

To find the angle measure of the missing angle, we have to note that the angle measures of a quadrilateral will all equal up to be 360°.

If we know 3 out of the 4 angles and the sum of the angles, we can add up the angles we know then subtract that from 360.

Number 1:

$87+112+92=291$

$360-291=69$

Number 2:

$124+71+68=263$

$360-263=97$

Number 3:

$95+46+74=215$

$360-215=145$

Number 4:

$72+49+89=210$

$360-210=150$

Number 5:

$69+65+98=232$

$360-232=128$

Number 6:

$77+123+86=286$

$360-286=74$

Hope this helped!

5 0

3 years ago

Find a fraction equivalent to 5/7 whose squared terms add up to 1184.

bogdanovich [222]

The system of equations of two unknowns is formulated and solved.

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left\{\begin{matrix} \ \ \ \dfrac{x}{y} = \dfrac{5}{7} \\ x^2+y^2 = 1184 \end{matrix}\right. \ \Longrightarrow \ x=\dfrac{5}{7}y } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ \left (\dfrac{5}{7}y \right )^2+y^2=1184\ \Longrightarrow\ 25y^2+49y^2=58016 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{74y^{2}=58016} \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ \ y^{2}=784 } \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf \bf{ \ \ \ \ \ y=\pm\sqrt{784}=\pm28 } \end{gathered}$}$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{ x=\dfrac{5}{7}(\pm 28)=\pm 20 } \end{gathered}$}$

The fraction that satisfies the request is $\bf{\dfrac{20}{28}}$ , since in $\bf{\dfrac{-20}{-28}}$ the negative signs are canceled and the first fraction is obtained.

3 0

2 years ago

A tetrahedron is a triangular pyramid with 4 equilateral faces. Han has a box of tetrahedrons with each of the 4 vertices marked

Daniel [21]

Theoretically, the number of the vertex comes at the top must be equal for infinitely many numbers of trials, but it's a tedious job to roll the dice for a large number of times. Rolling the tetrahedron only 10 times will not predict the correct result.

Han suspects that this tetrahedron is weighted in some way to make 1 appear more often than the other numbers.

So, check his suspect experimentally with the help of the concept of center of mass. A fair tetrahedron must have the center of mass at the center of the body.

The given tetrahedron has 4 equilateral triangular faces, so at first, measure all the sides of triangular faces and make sure that all are having the same length.

Then, conduct an experiment to check the location of the center of mass.

Hang the tetrahedron by attaching a thin string at the vertex 1 as shown in the figure and observe the base surface ( triangle 234) whether it is parallel to the ground or not.

Now, repeat the same by hanging it with vertices 2, 3, and 4 and observe the base surface.

For the center of mass to be located at the center of the tetrahedron, the base must be parallel to the ground (flat ground).i.e the hanging string must be perpendicular to the base for all the four cases.

If this is so, then the tetrahedron is a fair tetrahedron otherwise not.

8 0

3 years ago