What is the square root of 3.24

Sebastian is going to deposit $790 in an account that earns 6.8% interest compounded annually his wife Yolanda will deposit $815

strojnjashka [21]

Answer:

Step-by-step explanation:

Complete question

A) Sebastian's account will have about $28.67 less than Yolanda's account. B) Sebastian's account will have about $9.78 less than Yolanda's account. C) Yolanda's account will have about $28.67 less than Sebastian's account. D) Yolanda's account will have about $9.78 less than Sebastian's account.

For Sebastian

Amount = $P (1 + \frac{r}{n})^{nt}$

Substituting the given values we get

A =

$790 (1 + \frac{6.8}{100*1})^{3*1} \\962.367$

For Yolanda

Amount $= P(1+rt)$

$A = 815 (1 + \frac{7.2}{100}*3)\\A = 991.04$

Yolanda's account will have about $28.67 less than Sebastian's account

Option C is correct

5 0

3 years ago

How can i solve this maths problem z÷3=8

Delicious77 [7]

You would multiply both sides by 3 to cancel out the divide 3.
z÷3=8
z=24

4 0

4 years ago

Read 2 more answers

How would u do this? i needz helpz. plz helpz

castortr0y [4]

You have to add them all together and times that by 60%, when you get 13.8 that's the answer and to prove it, subtract 23-13.8 and you get 9.2 and that's 40%

3 0

3 years ago

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

3 years ago

Find the quotient of 13 divided by 325 what is the answer

lbvjy [14]

Answer:

1/25 or 0.04

Step-by-step explanation:

When you use 13/325 , you would get:

13/325

Divide by 13, we got:

1/25 or 0.04

Hope this helped :3

3 0

4 years ago