Answer:
radius ≈ 15.5
Step-by-step explanation:
the radius is RS
the angle between a tangent and the radius at the point of contact is 90°
then Δ RST is a right triangle
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
RS² + ST² = RT² ( substitute values )
RS² + 7² = 17²
RS² + 49 = 289 ( subtract 49 from both sides )
RS² = 240 ( take square root of both sides )
RS = ≈ 15.5 ( to 1 dec. place )
The two curves and
intersect at
and
, with
over
.
We have . The curves
and
intersect at
and
, with
over
.
Given:
A table of values of a linear function.
To find:
The slope, y-intercept and equation of the function.
Solution:
Take any two points on the table.
Let the points are (-1, -3) and (0, -6).
Slope of the line:
m = -3
Slope of the function = -3
y-intercept of the function is the point where x = 0.
In the table y = -6 when x = 0
y-intercept = -6
Equation of a line:
y = mx + c
where m is the slope and c is the y-intercept
y = -3x + (-6)
y = -3x - 6
Equation of a function is y = -3x - 6.