Answer: 18 units
Step-by-step explanation:since its is a horizontal line x2 - x1
7 -1 = 6
line 2:
since this is a vertical line y2 - y1
7 - 3 = 4
line 3:
since this is a horizontal line x2 - x1
7 - 4 = 3
line 4:
for this we need to use the distance formula which allows us to find the distance making a third point to form a right angle triangle
point 1: (1,3)
point 2: (4,7)
point 3 (new point) : (4,3)
now we can apply the pythogorean thereum (C squared = B squared + A squared) with the following lines.
line 1: (1,3) - (4,7)
line 2: (1,3) - (4,3)
line 3: (4,3) - (4,7)
line 1 squared = line2 squared + line 3 squared
calculate length of line 2 and 3
line 1 squared = (4 - 1) squared + (7 - 3) squared
line 1 squared = 3 squared + 4 squared
line 1 squared = 9 + 16
line 1 squared = 25
root both sides
line 1 = 5
add all the liens together
6 + 4 + 3 + 5 = 18
Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
<em>13.1</em>
Step-by-step explanation:
A = bh
~~~~~~~
= 16 , 
= 9
A = 16 × 9 = 144
From another side area of parallelogram with hight "h" base "b"
11h = 144
<em>h</em> = 144 ÷ 11 ≈ <em>13.1</em>
The horizontal distance is the difference of x-coordinates: 6 - 4 = 2.
The vertical distance is the difference of y-coordinates: -1 - (-2) = 1.
The straight-line distance (d) can be found using the Pythagorean theorem, since the vertical and horizontal distances are at right angles to each other.
.. d² = 2² + 1² = 5
.. d = √5 ≈ 2.2
The distance UV is about 2.2.
