Answer:
In Point Slope Form: y+6=4(x-1)
Step-by-step explanation:
<u>First you have to find the points given which are:</u>
<u>Label the points x1, y1, x2, and y2</u>
- It already gives you the slope which is 4.
<u>Plot the points in the equation of Point Slope Form:</u>
<em><u>y1-y2=m(x-x1)</u></em>
<u>Simplify: y1-6=4x-4</u>
<u>It doesn't ask you to simplify but why not! </u>
What’s in it for me will u give me vbucks
9514 1404 393
Answer:
- length: 29 ft
- width: 20 ft
Step-by-step explanation:
Assuming the dimensions are integer numbers of feet, you're looking for factors of 580 that have a difference of 9.
580 = 1×580 = 2×290 = 4×145 = 5×116 = 10×58 = 20×29
The last pair of factors differs by 9, so ...
the length is 29 feet; the width is 20 feet.
I believe it is $0.50.
$2 divided by 4 equals $0.50.
The computation shows that the placw on the hill where the cannonball land is 3.75m.
<h3>How to illustrate the information?</h3>
To find where on the hill the cannonball lands
So 0.15x = 2 + 0.12x - 0.002x²
Taking the LHS expression to the right and rearranging we have:
-0.002x² + 0.12x -.0.15x + 2 = 0.
So we have -0.002x²- 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x² + 0.03x -2 = 0.
This is a quadratic equation with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25.
The second solution y = 0.15 * 25 = 3.75
Learn more about computations on:
brainly.com/question/4658834
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Complete question:
The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2 . the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?
