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denis23 [38]
3 years ago
9

Write a program that prompts the user for a measurement inmeters and then converts it into miles, feet, and inches.

Computers and Technology
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

Program for measurement in meters and then converts it into miles, feet, and inches:

#include<iostream.h>

#include<conio.h>

void main()

{  float meter, mile, feet, inches;

 cout<<"enter meters";

 cin>>meters";

 feet=meter×3.2808;

 mile= meter×0.000621371;

 inches= meter×39.3701;

cout<<"Value of"<<meter<<"meter"<<"in feet is"<<feet<<"feet":

cout<<"Value of"<<meter<<"meter"<<"in mile is"<<mile<<"mile";

cout<<"Value of"<<meter<<"meter"<<"in inches is"<<inches<<"inches";

getch();

}

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Modify the list according to the following: append the smallest value at the end of the list when all numbers in the list are ne
ddd [48]

Answer:

The solution code is written in Python 3:

  1. def modifyList(listNumber):
  2.    posCount = 0
  3.    negCount = 0
  4.    for x in listNumber:
  5.        if x > 0:
  6.            posCount += 1
  7.        else:
  8.            negCount += 1
  9.    
  10.    if(posCount == len(listNumber)):
  11.        listNumber.append(max(listNumber))
  12.    
  13.    if(negCount == len(listNumber)):
  14.        listNumber.append(min(listNumber))
  15.    
  16.    print(listNumber)
  17. modifyList([-1,-99,-81])
  18. modifyList([1,99,8])
  19. modifyList([-1,99,-81])

Explanation:

The key step to solve this problem is to define two variables, posCount and negCount, to track the number of positive value and negative value from the input list (Line 2 - 3).

To track the posCount and negCount, we can traverse through the for-loop and create if else statement to check if the current number x is bigger than 0 then increment posCount by 1 otherwise increment negCount (Line 5- 9).

If all number in the list are positive, the posCount should be equal to the length of the input list and the same rule is applied to negCount. If one of them happens, the listNumber will append either the maximum number (Line 11 -12) or append the minimum number (Line 14-15).

If both posCount and negCount are not equal to the list length, the block of code Line 11 -15 will be skipped.

At last we can print the listNumber (Line 17).

If we test our function using the three sets of input list, we shall get the following results:

[-1, -99, -81, -99]

[1, 99, 8, 99]

[-1, 99, -81]

3 0
3 years ago
To conserve its public IP addresses, a company can instead use ____ addresses for devices within its own network boundaries.
Thepotemich [5.8K]

Answer:

private ip addresses

Explanation:

A private ip address is assigned to each device on a network, allowing devices on the same network to communicate with each other without using any public ip addresses.

7 0
2 years ago
Write a program to find the product of 3 numbers
ziro4ka [17]

Answer:

#include<iostream>

using namespace std;

int main()

{

   int a,b,c;

   cout<<"enter the value of a:";

   cin>>a;

   cout<<"enter the value of b:";

   cin>>b;

   cout<<"enter the value of c:";

   cin>>c;

   cout<<"product is:"<<(a*b*c);

   return 0;

}

Explanation:

6 0
3 years ago
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Call 334-399-4201 to annoyed my mom
yaroslaw [1]

Answer: why...

Explanation:

3 0
3 years ago
Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
leonid [27]

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = \mathbf{\bigg ( ( 42 -  (no. \ of \  failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \  comparisons) ) \bigg ) }

Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )

Total number of character comparison = 41 + 2

Total number of character comparison = 43

3 0
3 years ago
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