Answer:
Yes, if you want to be undetected.
Explanation:
It is vital to always use a command that will ensure that one's activity is undetected. This is one of the important rules of corporate organizations to keep their data and activities safe and secure. The commend provided is a useful tool for detective works especially the activities of criminals and hackers. Therefore, if the admin wants to be undetected, the command should not be used.
Answer:
The following statement is True.
Explanation:
Because when we are applying the pair t-test then, take differences of that pair and then treat it as an individual samples. Formula for the test is a statistic and in this case, it is also same as formula in the one-sample of t statistics.
Therefore, it will be an equivalent to the one-sample t-test.
I’m confused what are you trying to ask? What is the python?
Answer:
see explaination
Explanation:
#include <iostream>
#include <string>
using namespace std;
class LinkedList{
class Node{
public :
int data;
Node* next;
Node(int data){
this->data = data;
next = NULL;
}
};
public :
Node *head;
LinkedList(){
this->head = NULL;
}
void insert(int d){
Node* new_node = new Node(d);
new_node->next = head;
head = new_node;
}
// sort the list with selection sort algorithm.
// Pick the smallest element in the unsorted array and place in the first element in the unsorted.
void sort_list(){
if (head == NULL){
return;
}
Node* current = head;
while (current->next != NULL){
Node* min_node = current;
Node* traverse = current->next;
while(traverse != NULL){
if(traverse->data < min_node->data){
min_node = traverse;
}
traverse = traverse->next;
}
int temp = current->data;
current->data = min_node->data;
min_node->data = temp;
current = current->next;
}
}
void print_list(){
Node* current = head;
while(current !=NULL){
cout<<current->data<<" ";
current = current->next;
}
cout<<"\n";
}
};
int main(){
LinkedList ll;
for(int i=0;i<10;i++){
ll.insert(i);
}
ll.print_list();
cout<<"*******************************************\n";
ll.sort_list();
ll.print_list();
cout<<"*******************************************\n";
}
Answer:
true because then it would be like not popping out